/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Suppose the amplitude of a simpl... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose the amplitude of a simple pendulum having a bob of mass \(m\) is \(\theta_{0} .\) Find the tension in the string when the bob is at its extreme position.

Short Answer

Expert verified
The tension in the string is \(mg\) at the extreme position.

Step by step solution

01

Identify Parameters

The exercise involves a simple pendulum with a bob of mass \(m\) at its extreme position. The amplitude, \(\theta_0\), gives the maximum angular displacement from the vertical.
02

Understand Forces at Extreme Position

At the extreme position, the velocity of the pendulum bob is zero, and only the tension \(T\) in the string and the gravitational force (\(mg\)) act on the bob.
03

Apply Forces and Equilibrium

At the extreme position, the tension \(T\) has to balance the component of gravitational force acting towards the center of the circular path. In this position, all the gravitational force contributes to tension: \(T = mg \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amplitude
Amplitude in a simple pendulum refers to the maximum extent of displacement from its equilibrium position, which is the rest position when the pendulum is hanging vertically. In this context, the term "amplitude" is often denoted by the angle \( \theta_0 \) and represents the maximum angular displacement from the vertical axis.

Understanding amplitude is crucial, as it determines the motion range of the pendulum. If you imagine the pendulum swinging like a clock's minute hand, the amplitude would be how far the hand moves away from the 12 o'clock position. This angle doesn't change despite the mass or length of the pendulum and tells us the pendulum's path size.

At its extreme positions, the pendulum momentarily stops before reversing direction. At this point, its velocity is zero, but the amplitude gives us the extent of its potential energy. This energy states that the higher the amplitude, the more significant the potential energy that will transform into kinetic energy as the swing enters motion again.
Tension in String
In the simple pendulum, the tension in the string is the force exerted along the string that keeps the pendulum bob in motion along its arc. It acts towards the pivot point and is always perpendicular to the path of the pendulum. At the extreme position, where the pendulum is farthest from its equilibrium position, calculating the tension in the string is simpler yet crucial.

When the pendulum bob is at its extreme position, its velocity is zero, implying that tension must solely counteract gravitational pull components. Hence, the tension in the string equals the gravitational force acting on the bob, \(T = mg\). Here, \(m\) is the mass of the bob, and \(g\) is the acceleration due to gravity. It serves to maintain the bob within the pendulum's circular path.

Key things to remember about tension in a pendulum string:
  • Tension is greatest when the bob is at its highest potential energy point (the extreme position).
  • At the lowest point of the swing, tension keeps the centripetal force in motion as it has to support both the gravitational force and the force needed for circular motion.
Gravitational Force
Gravitational force is the downward pull exerted on objects due to Earth's gravity, calculated by the product of mass and gravitational acceleration. In a simple pendulum, this force acts consistently downwards throughout the bob's path, pulling it towards Earth's center.

While the pendulum swings, gravitational force serves two key roles:
  • At extreme positions, gravity acts to provide potential energy, preparing for the swing back toward equilibrium.
  • As the pendulum moves through its arc, gravity converts potential energy to kinetic energy and vice versa.


Fundamentally, for a pendulum of mass \(m\), the gravitational force is simply \(mg\), where \(g = 9.8\, m/s^2\). This force initiates the pendulum's movement and sustains it by providing the necessary convertive energy scope throughout the motion arc. Without gravity, a pendulum wouldn't have the means to keep swinging back and forth.

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Most popular questions from this chapter

A wave propagates on a string in the positive \(x\) -direction at a velocity \(v\). The shape of the string at \(t=t_{0}\) is given by \(g\left(x, t_{0}\right)=A \sin (x / a)\). Write the wave equation for a general time \(t .\)

Figure (15-E11) shows a string stretched by a block going over a pulley. The string vibrates in its tenth harmonic in unison with a particular tuning fork. When a beaker containing water is brought under the block so that the block is completely dipped into the beaker, the string vibrates in its eleventh harmonic. Find the density of the material of the block.

Two wires of different densities but same area of cross section are soldered together at one end and are stretched to a tension \(T\). The velocity of a transverse wave in the first wire is double of that in the second wire. Find the ratio of the density of the first wire to that of the second wire.

A wire of length \(2 \cdot 00 \mathrm{~m}\) is stretched to a tension of \(160 \mathrm{~N}\). If the fundamental frequency of vibration is \(100 \mathrm{~Hz}\), find its linear mass density.

A block of mass \(m\) moves on a horizontal circle against the wall of a cylindrical room of radius \(R\). The floor of the room on which the block moves is smooth but the friction coefficient between the wall and the block is \(\mu\). The block is given an initial speed \(v_{0}\). As a function of the speed \(v\) write (a) the normal force by the wall on the block, (b) the frictional force by the wall and (c) the tangential acceleration of the block. (d) Integrate the tangential acceleration \(\left(\frac{d v}{d t}=v \frac{d v}{d s}\right)\) to obtain the speed of the block after one revolution.

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