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A wire of length \(2 \cdot 00 \mathrm{~m}\) is stretched to a tension of \(160 \mathrm{~N}\). If the fundamental frequency of vibration is \(100 \mathrm{~Hz}\), find its linear mass density.

Short Answer

Expert verified
The linear mass density of the wire is \(0.001\ \text{kg/m}\).

Step by step solution

01

Identify the Given Variables

We are given the following values: the length of the wire, \( L = 2.00 \) m, the tension in the wire, \( T = 160 \) N, and the fundamental frequency of vibration, \( f = 100 \) Hz. We need to find the linear mass density, \( \mu \).
02

Recall Relationship for Fundamental Frequency

The fundamental frequency (\( f \)) of a wire under tension is related to tension \( T \), length \( L \), and linear mass density \( \mu \) by the formula \( f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} \).
03

Solve for Linear Mass Density

Rearrange the formula to solve for \( \mu \):\[ \mu = \frac{T}{(2L f)^2} \]
04

Substitute the Known Values

Substitute \( T = 160 \) N, \( L = 2.00 \) m, \( f = 100 \) Hz into the rearranged formula: \[ \mu = \frac{160}{(2 \times 2.00 \times 100)^2} = \frac{160}{(400)^2} \]
05

Calculate Linear Mass Density

Calculate \( \mu \) using the values:\[ \mu = \frac{160}{160000} = 0.001 \text{ kg/m} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

fundamental frequency
The fundamental frequency is the lowest frequency at which a string can vibrate. It is the first harmonic and plays a crucial role in the sound produced by vibrating strings. This concept is particularly important in musical instruments where strings produce sound. The fundamental frequency depends on several factors:

  • Length of the string: A longer string has a lower fundamental frequency.
  • Mass density of the string: Heavier strings generally vibrate at lower frequencies.
  • Tension in the string: Higher tension results in a higher frequency.

These factors combine to define the fundamental frequency using the formula for a stretched string: \[ f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} \] where:
  • \( f \) is the fundamental frequency in Hertz (Hz).
  • \( L \) is the length of the string in meters (m).
  • \( T \) is the tension in the string in Newtons (N).
  • \( \mu \) is the linear mass density in kilograms per meter (kg/m).
Understanding this formula helps in understanding how adjustments to a string affect its vibrations and the pitch of the sound it produces.
tension in wire
The tension in a wire is a measure of how tightly it is stretched and is crucial in determining its vibrational properties. When tension increases, the fundamental frequency of the wire's vibrations also increases. This is because tighter strings have less flexibility, resulting in faster vibrations.

The tension of a wire can be influenced by:
  • The force applied to stretch it: More force means more tension.
  • The material's elasticity: Stiffer materials can withstand more tension.

Tension plays a significant role in the production of sound. For instance, in musical instruments, increasing tension can raise the pitch. The relationship between tension \( T \), linear mass density \( \mu \), and the resulting vibrational frequency \( f \) of the wire is described by the equation:
\[ f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} \]
This illustrates that by controlling the tension, you can adjust the frequency and thereby modify the pitch of the sound produced by the wire.
string vibration
String vibration is the movement of strings that produces sound, an essential concept in acoustics. When a string is plucked or struck, it begins to vibrate, creating sound waves that we can hear. These vibrations occur at various frequencies, creating what is known as harmonics. The fundamental frequency is the simplest vibration pattern. Vibrations are influenced by:
  • How the string is set into motion (e.g., plucking or bowing).
  • The length, tension, and mass density of the string.

Other important concepts related to string vibrations include:
  • Nodes: Points of zero displacement along the string.
  • Antinodes: Points of maximum displacement.
Understanding these vibrations is key to multiple applications. In musical instruments, string vibration determines tone and pitch. By adjusting the length, mass density, or tension of a string, you can control the sound qualities. This makes string vibration a fundamental concept for those studying sound physics and musical acoustics.

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