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Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about \(39{\rm{ kJ}}/{\rm{g}}\). How many grams of fat will you gain if you eat \(10,000{\rm{ kJ}}\) (about \(2500{\rm{ kcal}}\)) one day and do nothing but sit relaxed for \(16.0{\rm{ hr}}\) and sleep for the other \(8.00{\rm{ h}}\)? Use data from Table 7.5 for the energy consumption rates of these activities.

Short Answer

Expert verified

The amount of fats gained is \(17.89{\rm{ g}}\).

Step by step solution

01

Step 1: Definition of Concepts 

Energy consumed: Energy consumed by any device is given as the product of its power rating and the time of operation of the device.

Mathematically,

\(E = PT\)

Here, P is the power and T is the time.

02

Calculate the amount of fat will you gain in grams

The energy used in sitting relaxed and sleeping is,

\({E_u} = {P_{sitting}} \times {t_{sleep}} + {P_{sleep}} \times {t_{sleep}}\)

Here, \({P_{sitting}}\) is the power consumed in sitting relaxed \(\left( {{P_{sitting}} = 120{\rm{ W}}} \right)\), \({t_{sitting}}\) is time spent in sitting relaxed \(\left( {{t_{sitting}} = 16.0{\rm{ h}}} \right)\), \({P_{sleep}}\) is the power consumed in sleeping \(\left( {{P_{sleep}} = 83\;{\rm{W}}} \right)\), and \({T_{sleep}}\) is the time spent in sleeping \(\left( {{T_{sleep}} = 8.0{\rm{ h}}} \right)\).

Putting all known values,

\(\begin{array}{c}{E_u} = \left( {120{\rm{ W}}} \right) \times \left( {16.0{\rm{ h}}} \right) + \left( {83{\rm{ W}}} \right) \times \left( {8.0{\rm{ h}}} \right)\\ = \left( {120{\rm{ W}}} \right) \times \left( {16.0{\rm{ h}}} \right) \times \left( {\frac{{3600{\rm{ s}}}}{{1{\rm{ h}}}}} \right) + \left( {83{\rm{ W}}} \right) \times \left( {8.0{\rm{ h}}} \right) \times \left( {\frac{{3600{\rm{ s}}}}{{1{\rm{ h}}}}} \right)\\ = 9302400{\rm{ J}} \times \left( {\frac{{1{\rm{ kJ}}}}{{1000{\rm{ J}}}}} \right)\\ = 9302.4{\rm{ kJ}}\end{array}\)

The unutilized energy is,

\(E = {E_c} - {E_u}\)

Here, \({E_c}\) is the energy consumed \(\left( {{E_c} = 10000{\rm{ kJ}}} \right)\).

Putting all known values,

\(\begin{array}{c}E = \left( {10000{\rm{ kJ}}} \right) - \left( {9302.4{\rm{ kJ}}} \right)\\ = 697.6{\rm{ kJ}}\end{array}\)

The body converts unutilized \(39{\rm{ kJ}}\) of energy into \(1{\rm{ g}}\) body fat. Therefore, the fat gain is,

\(\begin{array}{c}F = \frac{{697.6{\rm{ kJ}}}}{{\left( {39{\rm{ kJ}}/{\rm{g}}} \right)}}\\ = 17.89{\rm{ g}}\end{array}\)

Therefore, the required amount of fats gained is \(17.89{\rm{ g}}\).

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Most popular questions from this chapter

(a) Calculate the force needed to bring a 950-kg car to rest from a speed of 90.0 km/h in a distance of 120 m (a fairly typical distance for a non-panic stop).

(b) Suppose instead the car hits a concrete abutment at full speed and is brought to a stop in 2.00 m. Calculate the force exerted on the car and compare it with the force found in part (a).

Very large forces are produced in joints when a person jumps from some height to the ground.

(a) Calculate the magnitude of the force produced if an 80.0-kg person jumps from a 0.600–m-high ledge and lands stiffly, compressing joint material 1.50 cm as a result. (Be certain to include the weight of the person.)

(b) In practice the knees bend almost involuntarily to help extend the distance over which you stop. Calculate the magnitude of the force produced if the stopping distance is 0.300 m.

(c) Compare both forces with the weight of the person.

a) Calculate the work done on a 1500-kg elevator car by its cable to lift it 40.0 m at constant speed, assuming friction averages 100 N. b) What is the work done on the lift by the gravitational force in this process? c) What is the total work done on the lift?

A 75.0-kg cross-country skier is climbing a 3.0º slope at a constant speed of 2.00 m/s and encounters air resistance of 25.0 N. Find his power output for work done against the gravitational force and air resistance.

(b) What average force does he exert backward on the snow to accomplish this?

(c) If he continues to exert this force and to experience the same air resistance when he reaches a level area, how long will it take him to reach a velocity of 10.0 m/s?

(a) How fast must a 3000-kg elephant move to have the same kinetic energy as a 65.0-kg sprinter running at 10.0 m/s?

(b) Discuss how the larger energies needed for the movement of larger animals would relate to metabolic rates.

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