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Calculate the angle for the third-order maximum of 580-nm wavelength yellow light falling on double slits separated by 0.100 mm.

Short Answer

Expert verified

The angle for the third-order maximum for the yellow light is0.997°

Step by step solution

01

Given data

The wavelength of the yellow light is λ=580nm10-0m1nm=5.8×10-7m

The separation of the double slits is d=0.100mm1m1000mm=1×10-4m

02

Finding the angle which is the third-order maximum

A formula for the angle of the third-order maximum can be expressed as,

dsinθ=3λ…â¶Ä¦â¶Ä¦â¶Ä¦â¶Ä¦â¶Ä¦â¶Ä¦â¶Ä¦â¶Ä¦â¶Ä¦.(1)

Substituting the given data in equation (1), we get,

1×10-4m)×sinθ=3×(5.8×10-7m)θ=sin-11.74×10-6m1×10-4mθ=0.997°

Therefore, the angle for the third order of maxima is 0.997°.

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