91影视

The electromagnetic spectrum includes visible light, as we all know. The electromagnetic wave's speed is determined by

$\mathbf{c}\mathbf{=}\mathbf{惫位}$

We also know that visible light has wavelengths ranging from $\mathbf{380}\mathbf{}\mathbf{nm}\mathbf{}\mathbf{to}\mathbf{}\mathbf{760}\mathbf{}\mathbf{nm}$. As we all know, the wavelength of an electromagnetic wave in a medium is determined by

${\mathbf{位}}_{\mathbf{n}}\mathbf{=}\frac{\mathbf{位}}{\mathbf{n}}$

Where $\mathbf{n}$is the refraction index of the specified medium and $\mathbf{位}$is the wavelength of the electromagnetic wave in a vacuum. As we all know, any material's thickness is determined by

$\mathbf{t}\mathbf{=}\frac{\mathbf{位}}{\mathbf{n}}$

Young's double-slit experiment, as we all know, had unexpected findings. As we all know, light interacts with little objects, such as the narrow slits utilized by Young. For a double slit to produce constructive interference, the path length difference must be an integral multiple of the wavelength.

$\mathbf{dsin}\mathbf{\left(}\mathbf{胃}\mathbf{\right)}\mathbf{=}\mathbf{尘位}$

For a double slit to produce destructive interference, the path length difference must be a half-integral multiple of the wavelength.

$\mathbf{dsin}\mathbf{\left(}\mathbf{胃}\mathbf{\right)}\mathbf{=}\mathbf{(}\mathbf{m}\mathbf{+}\frac{\mathbf{1}}{\mathbf{2}}\mathbf{)}\mathbf{位}$

Where d is the distance between the slits, \({\rm{\theta }}\) is the angle of the beam from its initial direction, and $m$ is the interference order.

The third order's minimum angle is $\mathrm{胃}=48.6掳$.

The slit width is$\mathrm{d}=3\mathrm{渭尘}\left(\frac{{10}^{鈥�6}\mathrm{m}}{1\mathrm{渭尘}}\right)=3脳{10}^{鈥�6}\mathrm{m}$

Calculate for the third order, i.e., $\mathrm{m}=3$.

The path difference is supplied by, as we mentioned earlier in the concept session.

$\mathrm{dsin}\left(\mathrm{胃}\right)=\mathrm{尘位}$

Rearrange the equations to find the wavelength:

$$\begin{gathered} \mathrm{位}=\frac{\mathrm{dsin}\left(\mathrm{胃}\right)}{\mathrm{m}} \\ =\frac{\left(3脳{10}^{鈥�6}\mathrm{m}\right)脳\sin \left(48.6掳\right)}{3} \\ =7.5脳{10}^{鈥�7}\mathrm{m} \end{gathered}$$

Therefore, the wavelength of falling light is $\mathrm{位}=7.5脳{10}^{鈥�7}\mathrm{m}$.