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Chapter 27: Q13CQ (page 995)

What are the advantages of a diffraction grating over a prism in dispersing light for spectral analysis?

Short Answer

Expert verified

The advantages are it may be used to separate wavelengths, easily change the number of lines in the grating to suit a given application, and use both reflected and transmitted light.

Step by step solution

01

Define spectrum

When light passes through a prism or grating, it produces a spectrum due to dispersion, which is a range or band of different colors in the visible range.

02

Explanation

鈥� Higher-order fringe may be used to separate wavelengths, which is not achievable with a prism.

鈥� We can easily change the number of lines in the grating to suit a given application, but we can't do the same with the material's refractive index.

鈥� We can use both reflected and transmitted light, but only transmitted light may be used in a prism.

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Most popular questions from this chapter

Explain what happens to the energy carried by light that it is dimmed by passing it through two crossed polarizing filters.

Suppose pure-wavelength light falls on a diffraction grating. What happens to the interference pattern if the same light falls on a grating that has more lines per centimeter? What happens to the interference pattern if a longer-wavelength light falls on the same grating? Explain how these two effects are consistent in terms of the relationship of wavelength to the distance between slits.

Figure 27.55 shows the central part of the interference pattern for a pure wavelength of red light projected onto a double slit. The pattern is actually a combination of single slit and double slit interference. Note that the bright spots are evenly spaced. Is this a double slit or single slit characteristic? Note that some of the bright spots are dim on either side of the center. Is this a single slit or double slit characteristic? Which is smaller, the slit width or the separation between slits? Explain your responses.

Suppose a feather appears green but has no green pigment. Explain in terms of diffraction.

(a) As a soap bubble thins it becomes dark, because the path length difference becomes small compared with the wavelength of light and there is a phase shift at the top surface. If it becomes dark when the path length difference is less than one-fourth the wavelength, what is the thickest the bubble can be and appear dark at all visible wavelengths? Assume the same index of redfraction as water.

(b) Discuss the fragility of the film considering the thickness found.
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