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A microscope's ability to produce a picture of an object at a scale greater (or even smaller) than its actual size is known as magnification. Magnification is only beneficial when it is feasible to see more details of an object in a picture than when looking at it with the unaided eye.

$$\begin{gathered} m_{total}=800 \\ {m}_{obj}=200 \end{gathered}$$$$\begin{gathered} m_{total}=800 \\ {m}_{obj}=200 \end{gathered}$$

The magnification of the eyepiece can be obtained using the expression,

$$\begin{gathered} m_{total}=m_{obj}{m}_{eyepiece} \\ {m}_{eyepiece}=\frac{m_{total}}{m} \end{gathered}$$…â¶Ä¦â¶Ä¦â¶Ä¦..(1)

Substitute the given data in the above expression will give,

$m_{eyepiece}=4$

Therefore, the eyepiece's magnification is 4.

For the first objective ${m^1}_{obj}$ gets,

$$\begin{gathered} {m^1}_{obj}=100×\left(4\right) \\ =800 \end{gathered}$$

For the second objective role="math" localid="1654000885859" ${m^2}_{obj}$ gets,

$$\begin{gathered} {m^2}_{obj}=400×\left(4\right) \\ =1600 \end{gathered}$$

Therefore, the other total magnifications are 400 and 1600.