Q23PE Repeat the previous problem for ... [FREE SOLUTION]

Chapter 26: Q23PE (page 956)

Repeat the previous problem for glasses that are 2.20 cm from the eyes.

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The child's near point is 0.297 m.

Contact lenses operate by bending light to bring it into focus on the retina, where vision receptors collect data and send it to the brain.

P= 0.750D

You know that the near point for a normal relaxed eye is 0.25 m.

The power of the lens is equal to the reciprocal of the focal length is,

$P = \frac{1}{f} P = \frac{1}{d_{0}} + \frac{1}{d_{i}}$ 鈥︹赌︹赌︹赌︹赌︹赌︹赌�..(1)

Rearrange the distance between the far point and the person's eyes and solve equation (1) for it, where we obtained after substituting data values,

$\frac{1}{d_{0}} = P - \frac{1}{d_{i}} d_{0} = \frac{1}{P - \frac{1}{d}} = \frac{1}{0.750 D - \frac{1}{(0.25 m - 0.022 m)}} d_{0} = 0.275 m$

Solve for the glasses that are 2.2 cm, we will get

$d_{0} = x - 2.2 c m (\frac{1 m}{100 c m}) x = d_{0} + 0.22 m x = 0.275 m + 0.22 m x = 0.297 m$

Therefore, the near point for the child is 0.297 m.

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