Q13PE The power of a physician鈥檚 eye... [FREE SOLUTION]

Chapter 26: Q13PE (page 956)

The power of a physician鈥檚 eyes is 53.0 D while examining a patient. How far from her eyes is the feature being examined?

Short Answer

Expert verified

The feature is 33.3 cm from the physician's eyes.

Step by step solution

Definition of dioptre lens

The unit of measurement for the optical power of a lens or curved mirror is the dioptre of power of a lens, which is equal to the reciprocal of focal length.

Given information and Formula to be used

Power of the physician鈥檚 eyes P = 53.0 D.

The lens-to-retina distance is, $d_{i} = 2.00 c m (\frac{1 m}{100 c m}) = 0.02 m$ .

How far from her eyes is the feature being examined

The power of the eyes of a normal person can be calculated as,

$P = (\frac{1}{d_{鈭�}} + \frac{1}{d_{i}}) 53.0 D = (\frac{1}{0.02 m}) + \frac{1}{d_{鈭�}} \frac{1}{d_{鈭�}} = 3.0 D$

Substituting data values in the above expression gives,

$d_{鈭�} = \frac{1}{3.0 D} (\frac{1 D}{1 m^{- 1}}) = 0.334 m (\frac{100 c m}{1 m}) = 33.4 c m$

Therefore, the feature is 33.3 cm from the physician's eyes.

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91影视

The power of a physician鈥檚 eyes is 53.0 D while examining a patient. How far from her eyes is the feature being examined?

Short Answer

Step by step solution

Definition of dioptre lens

Given information and Formula to be used

How far from her eyes is the feature being examined

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