/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q21PE With 2.56脳106聽J聽 of heat tran... [FREE SOLUTION] | 91影视

91影视

With 2.56106J of heat transfer into this engine, a given cyclical heat engine can do only role="math" localid="1668687707360" 1.50105Jof work (a) What is the engine鈥檚 efficiency (b) How much heat transfer to the environment takes place.

Short Answer

Expert verified

Engine鈥檚 Efficiency is 0.0586 and amount of heat transfer to the environment is 2.41106J.

Step by step solution

01

Introduction

Heat Engine is a system which converts heat into work by taking heat from hot body (source) to carry out some work and there by discharging some of it at a very low temperature to cold body (sink). First and second law of thermodynamics helps in the operation of heat engine.

02

Parameters given and relationships-

Work done by the heat engine W=1.56105J

Heat transfer to the engine Q1=2.56106J

Engine efficiency (沙) =?

h=WQ1

Here

h-EfficiencyofHeatEngineW-WorddonebytheheatengineQ1-HeatTransfertotheHeatEngine

03

Calculation of efficiency and heat transfer to the environment

For efficiency-

h=WQ1=1.51052.56106=.0586

Heat Transfer to the environment 鈥

W=Q1-Q2Q2=Q1-WQ2=2.56106-1.50105Q2=2.41106J

Therefore, efficiency of the engine is 0.0586 and amount of heat transfer to the environment is 2.41106J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.