/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q5PE Repeat the seesaw problem in Exa... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Q5PE (page 316)

Repeat the seesaw problem in Example 9.1 with the center of mass of the seesaw \({\rm{0}}{\rm{.160}}\;{\rm{m}}\) to the left of the pivot (on the side of the lighter child) and assuming a mass of \({\rm{12}}{\rm{.0}}\;{\rm{kg}}\) for the seesaw. The other data given in the example remain unchanged. Explicitly show how you follow the steps in the Problem-Solving Strategy for static equilibrium

Short Answer

Expert verified

The \({\rm{32}}\;{\rm{kg}}\) child is \({\rm{1}}{\rm{.36}}\;{\rm{m}}\)from the pivot.

Step by step solution

01

Conservation of linear momentum

For a system, the linear momentum remains the same when no external force is acting).

02

Calculation of the distance

The mass is \({{\rm{m}}_{\rm{1}}}{\rm{ = 26}}\;{\rm{kg}}\).

The distance from the hinge is \({{\rm{r}}_{\rm{1}}}{\rm{ = 1}}{\rm{.60}}\;{\rm{m}}\).

The mass of the other is\({{\rm{m}}_{\rm{2}}}{\rm{ = 32}}\;{\rm{kg}}\)

The mass of the see-saw is \({{\rm{m}}_{\rm{s}}}{\rm{ = 12}}\;{\rm{kg}}\) .

The torque is zero about the pivot point. So, we can write,

\(\begin{array}{c}{{\rm{m}}_{\rm{1}}}{\rm{g}}{{\rm{r}}_{\rm{1}}}{\rm{ + }}{{\rm{m}}_{\rm{s}}}{\rm{g}}{{\rm{r}}_{\rm{s}}}{\rm{ = }}{{\rm{m}}_{\rm{2}}}{\rm{g}}{{\rm{r}}_{\rm{2}}}\\{\rm{26 \times 1}}{\rm{.6 + 12 \times 0}}{\rm{.16 = 32 \times }}{{\rm{r}}_{\rm{2}}}\\{{\rm{r}}_{\rm{2}}}{\rm{ = }}\frac{{{\rm{26 \times 1}}{\rm{.6 + 12 \times 0}}{\rm{.16}}}}{{{\rm{32}}}}\\{{\rm{r}}_{\rm{2}}}{\rm{ = 1}}{\rm{.36}}\;{\rm{m}}\end{array}\)

Hence, the distance is \({{\rm{r}}_{\rm{2}}}{\rm{ = 1}}{\rm{.36}}\;{\rm{m}}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Even when the head is held erect, as inFigure 9.41, its center of mass is not directly over the principal point of support (the atlantooccipital joint). The muscles at the back of the neck should therefore exert a force to keep the head erect. That is why your head falls forward when you fall asleep in the class. (a) Calculate the force exerted by these muscles using the information in the figure. (b) What is the force exerted by the pivot on the head?

The upper leg muscle (quadriceps) exerts a force of\({\rm{1250 N}}\), which is carried by a tendon over the kneecap (the patella) at the angles shown inFigure\({\rm{9}}{\rm{.38}}\). Find the direction and magnitude of the force exerted by the kneecap on the upper leg bone (the femur).

Scissors are like a double-lever system. Which of the simple machines inFigure 9.23andFigure 9.24is most analogous to scissors?

Suppose a \({\rm{900}}\;{\rm{kg}}\)car is on the bridge inFigure\({\rm{9}}{\rm{.34}}\)with its center of mass halfway between the hinges and the cable attachments. (The bridge is supported by the cables and hinges only.) (a) Find the force in the cables. (b) Find the direction and magnitude of the force exerted by the hinges on the bridge.

Question: A device for exercising the upper leg muscle is shown inFigure, together with a schematic representation of an equivalent lever system. Calculate the force exerted by the upper leg muscle to lift the mass at a constant speed. Explicitly show how you follow the steps in the Problem- Solving Strategy for static equilibrium inApplications of Statistics,Including Problem-Solving Strategies.
See all solutions

Recommended explanations on Physics Textbooks

Rotational Dynamics

Read Explanation

Conservation of Energy and Momentum

Read Explanation

Geometrical and Physical Optics

Read Explanation

Engineering Physics

Read Explanation

Electricity

Read Explanation

Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.