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Confirm that charge, electron family number, and the total number of nucleons are all conserved by the rule for β- decay given in the equation \(_Z^A{X_N} \to _{Z - 1}^A{Y_{N + 1}} + {\beta ^ - } + {v_e}\). To do this, identify the values of each before and after the decay.

Short Answer

Expert verified

The nucleons numbers are conserved.

Step by step solution

01

Define Radioactivity

The spontaneous emission of radiation in the form of particles or high-energy photons as a result of a nuclear process is known as radioactivity.

02

Identifying the values before and after decay

The reaction we have is:

\(_Z^A{X_N} \to _{Z - 1}^A{Y_{N + 1}} + {\beta ^ - } + {v_e}\)

The value of z is the initial charge.

The value (Z + 1} - - 1 = Z is the final charge.

As a result, charge is preserved. 2 millimeter The number of electrons in the first family is zero.

As, the value of β has a final electron family number of 1 and ve has a final electron family number of - 1, the overall electron family number is zero.

As a result, the number of electron families is preserved. (2 millimeter) The initial number of nucleons is A.

The value of A + 0 + 0 = A is the number of nucleons in the final state.

As a result, the number of nucleons remains constant.

Therefore, the nucleon numbers remain conserved.

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