Chapter 31: Q31.5-55PE (page 1117)
What fraction of the 40 K that was on Earth when it formed \(4.5 \times {10^9}\,{\rm{year}}\) ago is left today?
Short Answer
\(0.0874\)of the original \(^{40}\;{\rm{K}}\) is remaining today.
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Chapter 31: Q31.5-55PE (page 1117)
What fraction of the 40 K that was on Earth when it formed \(4.5 \times {10^9}\,{\rm{year}}\) ago is left today?
\(0.0874\)of the original \(^{40}\;{\rm{K}}\) is remaining today.
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A \({}^{{\rm{60}}}{\rm{Co}}\) source is labelled \(4.00\,{\rm{mCi}}\), but its present activity is found to be \(1.85 \times {10^7}\,{\rm{Bq}}\). (a) What is the present activity in \({\rm{mCi}}\)? (b) How long ago did it actually have a \({\rm{4}}{\rm{.00mCi}}\) activity?
Confirm that charge, electron family number, and the total number of nucleons are all conserved by the rule for electron capture given in theequation \(_Z^A{X_N} + {e^ - } \to _{Z - 1}^A{Y_{N + 1}} + {v_e}\). To do this, identify the values of each before and after the capture.
Verify that a\(2.3 \times {10^{17}}\,{\rm{km}}\)mass of water at normal density would make a cube\(60\,{\rm{km}}\)on a side, as claimed in Example\({\rm{31}}{\rm{.1}}\). (This mass at nuclear density would make a cube\(1.0\,{\rm{m}}\)on a side.)
\({{\rm{\beta }}^{\rm{ - }}}\)decay of \(^{40}K\) , a naturally occurring rare isotope of potassium responsible for some of our exposure to background radiation.
Construct Your Own Problem
Consider the decay of radioactive substances in the Earth's interior. The energy emitted is converted to thermal energy that reaches the earth's surface and is radiated away into cold dark space. Construct a problem in which you estimate the activity in a cubic meter of earth rock? And then calculate the power generated. Calculate how much power must cross each square meter of the Earth's surface if the power is dissipated at the same rate as it is generated. Among the things to consider are the activity per cubic meter, the energy per decay, and the size of the Earth.
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