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What lifetime do you expect for an antineutron isolated from normal matter?

Short Answer

Expert verified

The lifetime of an antineutron isolated from normal matter is small and stable without any change.

Step by step solution

01

Antineutron

The antineutron is the antiparticle of the neutron. It only varies from the neutron in that certain of its characteristics have the same magnitude as the neutron but have the opposite sign.

02

Lifetime of Antineutron

The usual short life of an antineutrino is due to its reactive nature with normal matter, as particles and antiparticles tend to annihilate. If an antineutrino were isolated from normal matter, it would behave equivalently to a usual neutrino, so we would expect it to be stable, as there are no lower energy states for it to decay to.

Therefore, the lifetime of antineutron is very short.

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Most popular questions from this chapter

(a) Find the charge, baryon number, strangeness, charm, and bottomness of the \({\rm{J/\psi }}\) particle from its quark composition.

(b) Do the same for the \(\Upsilon \) particle.

Accelerators such as the Triangle Universities Meson Facility (TRIUMF) in British Columbia produce secondary beams of pions by having an intense primary proton beam strike a target. Such "meson factories" have been used for many years to study the interaction of pions with nuclei and, hence, the strong nuclear force. One reaction that occurs is\({{\rm{\pi }}^{\rm{ + }}}{\rm{ + p}} \to {{\rm{\Delta }}^{{\rm{ + + }}}} \to {{\rm{\pi }}^{\rm{ + }}}{\rm{ + p}}\), where the \({{\rm{\Delta }}^{{\rm{ + + }}}}\)is a very short-lived particle. The graph in Figure \({\rm{33}}{\rm{.26}}\)shows the probability of this reaction as a function of energy. The width of the bump is the uncertainty in energy due to the short lifetime of the\({{\rm{\Delta }}^{{\rm{ + + }}}}\).

(a) Find this lifetime.

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(c) Draw a Feynman diagram of the production and decay of the \({{\rm{\Delta }}^{{\rm{ + + }}}}\)showing the individual quarks involved.

The primary decay mode for the negative pion \({\pi ^{\rm{ - }}} \to {{\rm{\mu }}^{\rm{ - }}}{\rm{ + }}{{\rm{\bar \upsilon }}_{\rm{\mu }}}\).

(a) What is the energy release in \({\rm{MeV}}\) in this decay?

(b) Using conservation of momentum, how much energy does each of the decay products receive, given the \({\pi ^{\rm{ - }}}\) is at rest when it decays? You may assume the muon antineutrino is massless and has momentum \(p = \frac{{{E_\nu }}}{c}\), just like a photon.

Beta decay is caused by the weak force, as are all reactions in which strangeness changes. Does this imply that the weak force can change quark flavor? Explain.

What length track does a \[{{\rm{\pi }}^{\rm{ + }}}\]traveling at 0.100c leave in a bubble chamber if it is created there and lives for \[{\rm{2}}{\rm{.60 \times 1}}{{\rm{0}}^{{\rm{ - 8}}}}{\rm{\;s}}\]? (Those moving faster or living longer may escape the detector before decaying.)

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