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Chapter 22: Q62PE (page 814)

Inside a motor, 30.0 Apasses through a 250-turn circular loop that is 10.0 cmin radius. What is the magnetic field strength created at its center?

Short Answer

Expert verified

The magnetic field strength calculated is 0.047 T.

Step by step solution

01

Step 1:Given data

The Current inside a motor isI=30.0A\

The number of turns in the loop isN=250turns

The radius of the wire isR=10.0cm1m100cm=0.10m

02

Determination of magnetic field

The magnetic impact of electric charges in relative motion and magnetized objects is described by a magnetic field, which is a vector field.

The following equation can be used to obtain the magnetic field strength created at the center,

B=(狈渭0I2R)鈥︹赌︹赌︹赌︹赌︹赌︹赌︹赌�.(1)

Where N,渭0,and R are the number of turns, the magnetic permeability of vacuum, and the radius of the wire, respectively.

03

Evaluating the magnetic field

Substitute the given data in equation (1), and we get,

B=狈渭0I2=250脳4蟺脳10-7N/m2脳30A2脳0.10m=0.047T

Therefore, the magnetic field strength is 0.047 T.

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