91影视

The current of the lightning bolt${}^{\mathbf{I}\mathbf{=}\mathbf{20}\mathbf{,}\mathbf{000}\mathbf{}\mathbf{A}}$

The earth鈥檚 magnetic field is${}^{\mathbf{B}\mathbf{=}\mathbf{3}\mathbf{.}\mathbf{00}\mathbf{脳}{\mathbf{10}}^{\mathbf{-}\mathbf{5}}\mathbf{}\mathbf{T}}$

The angle at the equator will be${}^{\mathbf{胃}\mathbf{=}{\mathbf{90}}^{\mathbf{掳}}}$

The magnetic force on a current-carrying conductor can be determined using the right-hand rule-1 such that, if fingers point towards the magnetic field and the thumb is in the direction of current then the palm will not be in the direction of magnetic force.

Quantitatively magnetic force can be estimated using the equation,

$\mathbf{F}\mathbf{=}\mathbf{ILBsin}\left(胃\right)$..................................(1)

(a)

To evaluate the force per meter, we use the equation and substitute the given data in equation (1), which results in

$$\begin{gathered} \frac{\mathbf{F}}{\mathbf{L}}\mathbf{=}\mathbf{IB}\mathbf{}\mathbf{sin}\mathbf{\left(}{\mathbf{90}}^{\mathbf{掳}}\mathbf{\right)} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{(}\mathbf{20}\mathbf{,}\mathbf{000}\mathbf{}\mathbf{A}\mathbf{)}\mathbf{脳}\mathbf{(}\mathbf{3}\mathbf{.}\mathbf{00}\mathbf{脳}\mathbf{1}{\mathbf{O}}^{\mathbf{-}\mathbf{5}}\mathbf{}\mathbf{T}\mathbf{}\mathbf{)}\mathbf{脳}\mathbf{1} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{6}\mathbf{}\mathbf{N}\mathbf{/}\mathbf{m} \end{gathered}$$

Hence, the force per meter is${}^{0.6\raisebox{1ex}{$\mathrm{N}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{m}$}\right.}$.

To obtain the direction of the force, we will be using the right-hand rule as stated above,

Now, adjust the thumb with the current's direction which is upwards, and then adjustthe fingers' direction to the magnetic field's direction which is towards the north (forward). Noticing that the palm will be facing towards the west(to the left) andtherefore the direction of the magnetic force will be towards the west or left.