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(a) By taking the slope of the curve in Figure 2.60, verify that the velocity of the jet car is\({\bf{115}}{\rm{ }}{\bf{m}}/{\bf{s}}\)at\(t = {\rm{ }}{\bf{20}}{\rm{ }}{\bf{s}}\). (b) By taking the slope of the curve at any point in Figure 2.61, verify that the jet car’s acceleration is\({\bf{5}}.{\bf{0}}{\rm{ }}{\bf{m}}/{{\bf{s}}^{\bf{2}}}\).

Short Answer

Expert verified

(a) The velocity is\(115.3 m/s\).

(b) The acceleration is approximately to the value \(5 m/{s^2}.\)

Step by step solution

01

velocity of the jet car is 115 m/s at t = 20 s

(a) Motion graphs can be used to analyse movement.

Graphical solutions for determining motion equations are identical to mathematical methods.

Velocity v is theslope of a graph of displacementx vs. time t.

Acceleration is the inclination of a graph of velocity v vs. time t.

Graphs can be used to calculate average velocity, instantaneous velocity, and acceleration.

Here the acceleration can be calculated by obtaining the slop

\(\begin{array}{l}m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_2}}}\\Here\,the\,coordinates\,are\,(7,0)\,\,\,and\,\,\,(20,1500)\\m = \frac{{1500 - 0}}{{20 - 7}}\\m = 115.3\,m/s\end{array}\)

Hence the velocity is \(115.3 m/s\)

02

slope of the curve at any point in Figure 2.61, verify that the jet car’s acceleration is 5.0 m/s2

(b) Here if we carefully look into the figure 2.61, in your text book lets take any two points on the line

Coordinate (0, 17) and (30,160)

Slop of the line will be

\(\begin{array}{l}m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_2}}}\\Here\,the\,coordinates\,are\,(0,17)\,\,\,and\,\,\,(30,160)\\m = \frac{{160 - 17}}{{30 - 0}}\\m = 4.766\,m/{s^2}\end{array}\)

Hence the acceleration is approximately to the value \(5 m/{s^2}.\)

The velocity is \(115.3 m/s\). The acceleration is approximately to the value \(5 m/{s^2}.\)

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Most popular questions from this chapter

(a) Sketch a graph of velocity versus time corresponding to the graph of displacement versus time given in Figure 2.55.

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(c) At which times is it zero?

(d) At which times is it negative?

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