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(a) A narrow beam of light containing yellow (580 nm) and green (550 nm) wavelengths goes from polystyrene to air, striking the surface at a30.0°incident angle. What is the angle between the colours when they emerge? (b) How far would they have to travel to be separated by 1.00 mm?

Short Answer

Expert verified
  1. The angle of yellow light is obtained as: 48.25°and the angle of green light is obtained as: 48.29°.
  2. The distance traveled must be obtained as: 1.43 m.

Step by step solution

01

Define Geometric Optics

Geometrical optics, often known as ray optics, is an optics model that describes light propagation using rays. In geometric optics, a ray is an abstraction that can be used to approximate the routes along which light propagates under particular conditions.

02

Evaluating the angle

To evaluate the angle of refraction for each light color using Snell's law:nisinθi=nfsinθf.

The value ofnf=1.000.

The angle evaluated for yellow light is:

θf=sin-1nisinθinf=sin-11.492×sin30.00°1.000=48.25°

Therefore, the angle for yellow light is: 48.25°.

The angle evaluated for green light is:

θf=sin-1nisinθinf=sin-11.493×sin30.00°1.000=48.29°

Therefore, the angle for yellow light is: 48.29°.

03

Evaluating the distance

b. The law of trigonometry is: tanθ=∆y∆x.

The value of∆y=1.00mm and then we solve for the value of ∆x.

It is then evaluated as:

∆x=∆ytanθf=1.00×10-3mtan0.04°=1.43m

Therefore, the distance is: 1.43m.

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