/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q69PE If you want a characteristic RL ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If you want a characteristic RL time constant of 1.00 s, and you have a resistor 500Ω, what value of self-inductance is needed?

Short Answer

Expert verified

The value of self-inductance is 500 H

Step by step solution

01

Given Data

The time constant of the RL circuit is Ï„=1.00s

The value of resistance isR=500Ω

02

Concept Introduction

The trait of a current-carrying coil that resists or opposes the change in current flowing through it is known as self-inductance. This is mostly owing to the self-induced emf generated by the coil.

03

Calculating the Value of Self-Inductance

In RL circuits, the time constant,Ï„, can be expressed as,

Ï„=LR…â¶Ä¦â¶Ä¦â¶Ä¦â¶Ä¦.(1)

Rearrange equation (1) for the self-inductance and the substitute the given data, such that

L=τRL=(1.00s)×500Ω=500H

Therefore, the self-inductance is 500 H

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.