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Chapter 23: Q16PE (page 860)

Distances in space are often quoted in units of light years, the distance light travels in one year. (a) How many meters is a light year? (b) How many meters is it to Andromeda, the nearest large galaxy, given that it is2.0脳106 light years away? (c) The most distant galaxy yet discovered is12.0脳109 light years away. How far is this in meters?

Short Answer

Expert verified
  1. The one light-year is 9.47脳1015m.
  2. The value of meters that makes an Andromeda is1.894脳1022m.
  3. The value of the distance is 1.136脳1026m.

Step by step solution

01

Define distance-time theory.

Distance-time theory defines distance as equivalent to a time period according to the equation

D= ct鈥︹�︹�︹�︹�︹��(1)

02

Given information and Formula to be used

t=1year=365.25days脳24h1day脳60min1h脳60s1min=3.156脳107sc=3脳108m/s

d1=2.0脳106light-year

d2=12.0脳109light-year

03

Calculate the value of meters that results in a light year.

(a)

We use equation (1) and substitute the given data such that,

d=3脳108m/s脳3.156脳107Sd=9.47脳1015m

Therefore, one light-year is d=9.47脳1015m.

04

Calculate the value of meters that makes an Andromeda.

(b)

For d1=2.0脳106light-year, the distance is given by,

d1=2.0脳106light-year9.47脳1015m1light-yeard1=1.894脳1022m

Therefore, the value of meters that makes an Andromeda is 1.894脳1022m.

05

Calculate the value of distance in meters of the most distant galaxy yet discovered.

(c)

For 12.00脳109the light-year, the distance is given by,

d2=12.00脳109light-year9.47脳1015m1light-yeard2=1.136脳1026m

Therefore, the value of the distance is 1.126脳1026m.

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