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An\({\rm{emf}}\)is induced by rotating a\({\rm{1000 - }}\)turn,\({\rm{20}}{\rm{.0 cm}}\)diameter coil in the Earth’s\({\rm{5}}{\rm{.00 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{ T}}\)magnetic field. What average\({\rm{emf}}\)is induced, given the plane of the coil is originally perpendicular to the Earth’s field and is rotated to be parallel to the field in\({\rm{10}}{\rm{.0 ms}}\)?

Short Answer

Expert verified

The average \({\rm{emf}}\) induced is obtained as \({\rm{1}}{\rm{.57}}\;{\rm{mV}}\).

Step by step solution

01

Define Electromagnetic Induction

The creation of an electromotive force across an electrical conductor in a changing magnetic field is known as electromagnetic or magnetic induction. Induction was discovered in\({\rm{1831}}\)by Michael Faraday, and it was mathematically characterized as Faraday's law of induction by James Clerk Maxwell.

02

Evaluating the average emf induced

The electromotive force is induced when a coil with the value\({\rm{N}}\)turns experiences a flux change of the value\({\rm{\Delta \Phi }}\)in time\({\rm{\Delta t}}\)is given by:

\({\rm{E = - N}}\frac{{{\rm{\Delta \Phi }}}}{{{\rm{\Delta t}}}}\)……………….(1)

The flux reaches the point zero from the maximal value under the given time, we can simply write the change in flux as:

\(\begin{aligned}{}{\rm{\Delta \Phi = 0 - BA}}\\{\rm{ = - BA}}\end{aligned}\)

The emf then will be:

\({\rm{\varepsilon = }}\frac{{{\rm{NBA}}}}{{\rm{t}}}\)……………………….(2)

Substituting the area such that:

\(\begin{aligned}{}{\rm{A = \pi }}{{\rm{R}}^{\rm{2}}}\\{\rm{ = }}\frac{{{\rm{\pi }}{{\rm{D}}^{\rm{2}}}}}{{\rm{4}}}\end{aligned}\)

Therefore the analytical result is,

\({\rm{\varepsilon = }}\frac{{{\rm{\pi NB}}{{\rm{D}}^{\rm{2}}}}}{{\rm{4}}}\)………………………(3)

The numerical value is then evaluated as:

\(\begin{aligned}{}{\rm{\varepsilon }} &= \frac{{{\rm{\pi \times 1000 \times }}\left( {{\rm{5 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\;{\rm{T}}} \right){\rm{ \times }}{{\left( {{\rm{0}}{\rm{.2}}\;{\rm{m}}} \right)}^{\rm{2}}}}}{{\rm{4}}}\\ &= {\rm{1}}{\rm{.57\;}} \times {\rm{1}}{{\rm{0}}^{ - {\rm{3}}}}\;{\rm{V}}\left( {\frac{{1\;{\rm{mV}}}}{{{\rm{1}}{{\rm{0}}^{ - {\rm{3}}}}\;{\rm{V}}}}} \right)\\ &= {\rm{1}}{\rm{.57}}\;{\rm{mV}}\end{aligned}\)

Therefore, the average \({\rm{emf}}\) induced is obtained as \({\rm{1}}{\rm{.57}}\;{\rm{mV}}\).

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Most popular questions from this chapter

What is the peak emf generated by rotating a 1000-turn, \({\rm{5}}{\rm{.00 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{ T}}\) diameter coil in the Earth’s magnetic field, given the plane of the coil is originally perpendicular to the Earth’s field and is rotated to be parallel to the field in \({\rm{10}}{\rm{.0 ms}}\)?

Verify that after a time of \(10.0{\rm{ }}ms\), the current for the situation considered in Example \(23.9\) will be \(0.183{\rm{ }}A\) as stated.

In the August 1992space shuttle flight, only 250 mof the conducting tether considered in Example 23.2could be let out. A 40.0 Vmotional emf was generated in the Earth's 5.00×10-5Tfield, while moving at7.80×103m/s. What was the angle between the shuttle’s velocity and the Earth’s field, assuming the conductor was perpendicular to the field?

A \({\rm{25}}{\rm{.0 H}}\) inductor has \({\rm{100 A}}\) of current turned off in \({\rm{1}}{\rm{.00 ms}}{\rm{.}}\) (a) What voltage is induced to oppose this? (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?

(a) A lightning bolt produces a rapidly varying magnetic field. If the bolt strikes the earth vertically and acts like a current in a long straight wire, it will induce a voltage in a loop aligned like that in Figure\({\rm{23}}{\rm{.57}}\)(b). What voltage is induced in a 1.00 m diameter loop\({\rm{50}}{\rm{.0 m}}\)from a\({\rm{2}}{\rm{.00 \times 1}}{{\rm{0}}^{\rm{6}}}{\rm{ A}}\)lightning strike, if the current falls to zero in\({\rm{25}}{\rm{.0 \mu s}}\)? (b) Discuss circumstances under which such a voltage would produce noticeable consequences.

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