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Chapter 19: Q63PE (page 698)

(a) What is the energy stored in the 10.0渭贵capacitor of a heartdefibrillator charged to 9.00脳103V? (b) Find the amount of storedcharge.

Short Answer

Expert verified
  1. The stored energy is 405 J.
  2. The charge stored is 0.09 C

Step by step solution

01

Given Data

The capacitance of the capacitor is:

C=(10.0渭贵)(1F106渭贵)=10.0脳10-6F

The voltage between the capacitor plates is:螖痴=9.00脳103V

02

Calculating for part (a) energy of capacitor

The stored energy for a capacitor of capacitancewith a potential difference between the platesis given by:

UE=12C(螖痴)2

a)

The capacitance C is defined as charge stored per unit potential difference

C=Q(螖痴)

Thus, entering the values of C and 螖V, we obtain:

UE=12(10.0脳10-6F)(9.00脳103V)=405J

Therefore, stored energy isrole="math" localid="1654921309243" UE=405 J

03

Calculating for part (b), stored charge

b)

The stored charge is given as

Q=C脳螖V

Substitute numerical values:

Q=(10.0脳10-6F)(9.00脳103V)=0.09C

Therefore, the charge accumulated on capacitor plates islocalid="1654921503322" Q=0.09C

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In what region of space is the potential due to a uniformly charged sphere the same as that of a point charge? In what region does it differ from that of a point charge?

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Integrated Concepts

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Sketch the equipotential lines for the two equal positive charges shown in Figure. Indicate the direction of increasing potential.
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