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Suppose a speck of dust in an electrostatic precipitator has 1.0000×1012 protons in it and has a net charge of -5.00 nC (a very large charge for a small speck). How many electrons does it have?

Short Answer

Expert verified

The number of electrons in the speck of dust is 1.0312×1012.

Step by step solution

01

Charged body

A body is said to be charged when it has unequal number of electrons and protons. If the body has greater number of electrons than protons, the body is said to be negatively charged.

02

Number of electrons responsible for negative charge in the speck of dust

According to the quantization of charge,

Q = ne

Here, Q is the total charge on the body due to excess electrons (Q=-5.00 nC) , is the number of electrons responsible for the negative charge on the body, and is the charge on electron e=-1.6×10-19C.

The number of electrons responsible for the negative charge on body is,

n=Qe

Substituting all known values,

n=-5.00nC1.6×10-19C=3.125×1010

03

Total number of electrons in the speck of dust

The total number of electrons on a negatively charged body is,

nt = ne + n

Here, n is the total number of electrons on an negatively charged body, ne is the number of electrons to neutralize the charge of protons ne=1.0000×1012 , and n is the number of electrons responsible for negative charge on the body n=3.125×1010.

Substituting all known values,

nt=1.0000×1012+3.1250×1010=1.0312×1012

Hence, the number of electrons in the speck of dust is 1.0312×1012.

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