91影视

The rate of electron flow can be described as the aggregate flow of electrons via a wire. The term "resistance" refers to anything that stands in the way of current flow. To convert electrical energy to light, heat, or movement, an electrical circuit must have resistance.

(a)

The circuit diagram of the connection of an ammeter when a $0.02\mathrm{惟}$ammeter is placed in series with a$10\mathrm{惟}$resistor in a circuit is given below,

Therefore, the circuit diagram is obtained.

(b)

A $0.02\mathrm{惟}$ammeter is placed in series with a $10\mathrm{惟}$resistor in a circuit.

The formula for total resistance is,

$$\begin{gathered} {\mathrm{R}}_{\mathrm{combination}}=\mathrm{R}+\mathrm{r} \\ =10\mathrm{惟}+0.02\mathrm{惟} \\ =10.02\mathrm{惟} \end{gathered}$$

Therefore, the value for total resistance is ${\mathrm{R}}_{\mathrm{combination}}=10.02\mathrm{惟}$.

(c)

Current through the only resistor is,

$$\begin{gathered} \mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}} \\ =\frac{\mathrm{V}}{10\mathrm{惟}} \end{gathered}$$

And current through combination is,

$$\begin{gathered} {\mathrm{I}}_{\mathrm{combination}}=\frac{\mathrm{V}}{{\mathrm{R}}_{\mathrm{combination}}} \\ =\frac{\mathrm{V}}{10.02\mathrm{惟}} \end{gathered}$$

The decrease in current is,

$$\begin{gathered} {\mathrm{P}}_{\mathrm{d}}=\left(\frac{{\mathrm{I}}_{\mathrm{combination}}-\mathrm{I}}{\mathrm{I}}\right)脳100\% \\ =\left(\frac{\left({\displaystyle \frac{\mathrm{V}}{10.02\mathrm{惟}}}\right)-\left({\displaystyle \frac{\mathrm{V}}{10\mathrm{惟}}}\right)}{\left({\displaystyle \frac{\mathrm{V}}{10\mathrm{惟}}}\right)}\right)脳100\% \\ =-0.1996\% \end{gathered}$$

Therefore, the decrease in current is $0.1996\%$.

(d)

Voltage through the only resistor is,

$$\begin{gathered} \mathrm{V}=\mathrm{IR} \\ =\mathrm{I}脳10\mathrm{惟} \end{gathered}$$

And voltage through combination is,

$$\begin{gathered} {\mathrm{V}}_{\mathrm{Combination}}={\mathrm{IR}}_{\mathrm{Combination}} \\ =\mathrm{I}脳10.02\mathrm{惟} \end{gathered}$$

The increase in voltage is,

$$\begin{gathered} {\mathrm{P}}_{\mathrm{I}}=\left(\frac{{\mathrm{V}}_{\mathrm{Combination}}-\mathrm{V}}{\mathrm{V}}\right)脳100\% \\ =\left(\frac{\left(\mathrm{I}脳10.02\mathrm{惟}\right)-\left(\mathrm{I}脳10\mathrm{惟}\right)}{\left(\mathrm{I}脳10\mathrm{惟}\right)}\right)脳100\% \\ =0.2\% \end{gathered}$$

Therefore, the increase in voltage is $0.2\%$.

(e)

The result for the decrease in current is $0.1996\%$.

The result ofthe increase in voltage is $0.2\%$.

These are very small amounts, so they do not affect the circuit in anyway.

Therefore, the results are not significant.