/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q35PE Apply the junction rule at point... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 21: Q35PE (page 776)

Apply the junction rule at point a in Figure 21.52.

Short Answer

Expert verified

Using the junction rule on point 'a', we obtained:

I3=I2+I1

Step by step solution

01

Definition of Kirchhoff's law

Kirchhoff's first law defines currents at circuit junctions. It states that the sum of currents flowing into and out of a junction in an electrical circuit equals the sum of currents flowing out of the junction.

02

Explanation for the junction rule

The sum of currents entering the junction equals the sum of currents leaving the junction, according to the junction rule. An equation may be written for point an in the figure 21.55 using the following rule:

I3=I2+I1

Hence current at location 'a' can be calculated using Kirchhoff's Junction rule as follows:

I3=I2+I1

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose you are doing a physics lab that asks you to put a resistor into a circuit, but all the resistors supplied have a larger resistance than the requested value. How would you connect the available resistances to attempt to get the smaller value asked for?

Two different 12-Vautomobile batteries on a store shelf are rated at 600and 850鈥渃old cranking amps.鈥� Which has the smallest internal resistance?

A flashing lamp in a Christmas earring is based on an RCdischarge of a capacitor through its resistance. The effective duration of the flash is 0.250 s , during which it produces an average 0.500 W from an average 3.00 V (a) What energy does it dissipate? (b) How much charge moves through the lamp? (c) Find the capacitance. (d) What is the resistance of the lamp?

A car battery with a 12-V emf and an internal resistance of 0.050惟is being charged with a current of 60 A Note that in this process the battery is being charged. (a) What is the potential difference across its terminals? (b) At what rate is thermal energy being dissipated in the battery? (c) At what rate is electric energy being converted to chemical energy? (d) What are the answers to (a) and (b) when the battery is used to supply 60 A to the starter motor?

(a) Calculate the capacitance needed to get an \(RC\)time constant of \(1.00 \times {10^3}\;s\) with a \(0.100 - \Omega \) resistor. (b) What is unreasonable about this result?(c) Which assumptions are responsible?
See all solutions

Recommended explanations on Physics Textbooks

Solid State Physics

Read Explanation

Electrostatics

Read Explanation

Engineering Physics

Read Explanation

Measurements

Read Explanation

Energy Physics

Read Explanation

Fluids

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.