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The acceleration of the spacecraft in which the Apollo astronauts took off from the moon was \(3.4 \mathrm{m} / \mathrm{s}^{2} .\) On the moon, \(g=1.6 \mathrm{m} / \mathrm{s}^{2} .\) What was the apparent weight of a \(75 \mathrm{kg}\) astronaut during takeoff?

Short Answer

Expert verified
The apparent weight of the astronaut during takeoff was 135 N.

Step by step solution

01

Identify the Given Values

Here are the given values - Gravitational acceleration on moon (\(g\)) = 1.6 m/s², lift-off acceleration of spacecraft (\(a\)) = 3.4 m/s², and the astronaut's mass (\(m\)) = 75 kg.
02

Calculate the Net Acceleration

The net acceleration (\(a_{net}\)) is the difference between the lift-off acceleration and moon's gravitational pull: \(a_{net} = a - g = 3.4 m/s² - 1.6 m/s² = 1.8 m/s²\).
03

Calculate the Apparent Weight

The apparent weight can be calculated by multiplying the astronaut's mass with the net acceleration. Apparent weight (\(W_{apparent}\)) = \(m \cdot a_{net} = 75 kg \cdot 1.8 m/s² = 135 N\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Acceleration
Gravitational acceleration is a measure of the force of gravity at a particular location. On Earth, this value is approximately recognized as 9.81 meters per second squared (\(9.81 \text{ m/s}^2\)), but it can vary depending on where you are on the planet's surface. For celestial bodies like the moon, this acceleration due to gravity is much less because of its smaller mass compared to Earth's. In our exercise, the gravitational acceleration on the moon is given as 1.6 meters per second squared (\(1.6 \text{ m/s}^2\)).

This has critical implications when calculating forces that involve gravity, such as the apparent weight of objects or astronauts' real weight when they are off-planet. The gravitational acceleration is a vector quantity—it has both a magnitude and a direction, which is toward the center of the celestial body.
Net Acceleration
Net acceleration describes the overall acceleration of an object, taking into account all acting forces. In the context of moving objects, especially in environments with different gravitational forces like the moon, it is crucial to consider the net effect of both the gravitational acceleration and other accelerations, such as the propulsion of a spacecraft. In our exercise, the net acceleration is simply the difference between the lift-off acceleration of the spacecraft and the moon's gravitational pull.

To calculate it, we subtract the gravitational acceleration (\(g\text{ of moon}\)) from the lift-off acceleration (\(a\text{ of spacecraft}\)):
\(a_{net} = a - g\text{.}\) This resultant acceleration affects the apparent weight of the astronauts during takeoff, making it a critical factor in designing spacecraft and evaluating astronauts' experiences during launch.
Newton's Second Law
Newton's Second Law of Motion states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (\(F = m \times a\text{.}\)). This law forms the foundation for understanding motion and forces in physics, telling us how an object will move under the influence of a given force.

When calculating the apparent weight, which is essentially the normal force experienced by the astronauts in a non-inertial frame of reference, we use a form of Newton's Second Law. In our textbook problem, we applied it by multiplying the mass (\(m\text{ of astronaut}\)) with the net acceleration (\(a_{net}\text{.}\)) This calculation gives us the 'apparent weight' during the lift-off and helps us understand the forces that astronauts feel, which differ significantly from the force they would experience due to gravity alone while standing still on the moon’s surface.

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Most popular questions from this chapter

In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A rider is towed at a constant speed by a rope that is at an angle of \(15^{\circ}\) from horizontal. The tension in the rope is \(2300 \mathrm{N}\). The force of the sail on the rider is \(30^{\circ}\) from horizontal. What is the weight of the rider?

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In a head-on collision, a car stops in 0.10 s from a speed of \(14 \mathrm{m} / \mathrm{s} .\) The driver has a mass of \(70 \mathrm{kg},\) and is, fortunately, tightly strapped into his seat. What force is applied to the driver by his seat belt during that fraction of a second?

A crate pushed along the floor with velocity \(\vec{v}_{\mathrm{i}}\) slides a distance \(d\) after the pushing force is removed. a. If the mass of the crate is doubled but the initial velocity is not changed, what distance does the crate slide before stopping? Explain. b. If the initial velocity of the crate is doubled to \(2 \vec{v}_{\mathrm{i}}\) but the mass is not changed, what distance does the crate slide before stopping? Explain.

\(\mathrm{A} 23 \mathrm{kg}\) child goes down a straight slide inclined \(38^{\circ}\) above horizontal. The child is acted on by his weight, the normal force from the slide, and kinetic friction. a. Draw a free-body diagram of the child. b. How large is the normal force of the slide on the child?

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