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In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A rider is towed at a constant speed by a rope that is at an angle of \(15^{\circ}\) from horizontal. The tension in the rope is \(2300 \mathrm{N}\). The force of the sail on the rider is \(30^{\circ}\) from horizontal. What is the weight of the rider?

Short Answer

Expert verified
The weight of the rider is equivalent to the vertical component of the tension in the rope, which will be evaluated using the given values.

Step by step solution

01

Identify Known Quantities

The known quantities are the angle at which the rider is being towed, \(15^{\circ}\), the tension in the rope, \(2300 \mathrm{N}\), and the angle of force on the sail, \(30^{\circ}\). We are to find the weight of the rider.
02

Resolve the Tension Force into Components

The tension in the rope can be resolved into horizontal and vertical components using trigonometry: \nHorizontal Component: \(T_{x}= 2300 \cos (15^{\circ})\)\nVertical Component: \(T_{y} = 2300 \sin (15^{\circ})\)
03

Apply Newton’s Second Law

According to Newton's second law, the summation of forces is equal to the mass of the object times its acceleration. However, the rider is moving at a steady speed, hence the net force along the vertical direction should be zero. Thus, the gravitational force (weight) is equal to the vertical component of the force exerted by the sail. Hence the weight of the rider \(W\) can be calculated using the equation: \n\(W = T_{y}\)
04

Calculation

Substitute the value of \(T_{y}\) in the equation: \(W = T_{y} = 2300 \sin (15^{\circ})\)\nCalculate the value to get the weight in Newtons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
In physics, Newton's Second Law is a principal concept that outlines the relationship between an object and the forces acting upon it. It is generally expressed in the formula: \[ F = ma \] Here, \( F \) represents the total force acting on an object, \( m \) is the mass of the object, and \( a \) is the acceleration it experiences. This law highlights that the acceleration of an object is directly proportional to the net force acting upon it and inversely proportional to its mass.

In the context of parasailing, the rider is towed at a constant speed which means the net force is zero, especially in the vertical direction. Therefore, by applying Newton's Second Law, the vertical component of the tension force must balance out the rider's gravitational force (weight). The formula transforms into a simple balance equation, where the vertical force component equals the weight.
Trigonometry in Physics
Trigonometry helps us to resolve various force components in physics, especially when dealing with angles. In parasailing, the problem involves tensions and forces at specific angles. Resolving these forces into horizontal and vertical components helps us analyze their effects on the system.

For any force vector represented by magnitude \( T \) and angle \( \theta \):
  • The horizontal component is expressed as \( T_x = T \cos(\theta) \)
  • The vertical component is expressed as \( T_y = T \sin(\theta) \)
By applying trigonometry, we can dissect the tension in the rope into these components. In this parasailing exercise, the problem required finding the weight based on the vertical component of force. Using \( T_y = 2300 \sin(15^{\circ}) \), we effectively separate the vertical component from the angled tension force.
Equilibrium of Forces
Equilibrium of forces occurs when all acting forces on an object balance each other out, resulting in a net force of zero. In terms of parasailing, maintaining constant speed at a specific altitude signifies equilibrium.

Equilibrium in the vertical direction means the upward force (vertical component of tension) must equal the downward gravitational force (weight of the rider). The vertical force ensures the rider remains at a steady altitude, neither ascending nor descending. Ensuring this balance pertains to the basic principle of equilibrium in forces:\[ \sum F_y = T_y - W = 0 \] Here, \( T_y \) represents the upward force component, while \( W \) is the downward weight. The equality reveals that the parasailer experiences no vertical acceleration, validating the equilibrium condition.

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Most popular questions from this chapter

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