/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 As we've seen, protons have an i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

As we've seen, protons have an inherent magnetic moment, which has been measured to be \(1.4 \times 10^{-26} \mathrm{A} \cdot \mathrm{m}^{2} .\) What would be the torque on a proton whose moment was oriented at \(90^{\circ}\) to a \(1.2 \mathrm{T}\) magnetic field?

Short Answer

Expert verified
The torque on the proton would be \(1.68 \times 10^{-26} \mathrm{N} \cdot \mathrm{m}\).

Step by step solution

01

Understand the Problem

A proton has a magnetic moment of \(1.4 \times 10^{-26} \mathrm{A} \cdot \mathrm{m}^{2}\). The torque (\(\tau\)) on this proton needs to be found when it is placed in a magnetic field (\(B\)) of \(1.2 \mathrm{T}\) at an angle of \(90^{\circ}\) to the field.
02

Formulate the Torque Equation

The torque (\(\tau\)) on a magnetic moment (\(\mu\)) in a magnetic field is given by the vector product of the magnetic moment and the magnetic field, which can be expressed as \(\tau = \mu \times B\). The magnitude of this torque can be given by \(\tau = \mu B \sin(\theta)\), where \(\theta\) is the angle between \(\mu\) and \(B\).
03

Substitute the given Values

Substituting the given values into the formula, we get \(\tau = (1.4 \times 10^{-26} \mathrm{A} \cdot \mathrm{m}^{2}) (1.2 \mathrm{T}) \sin(90^{\circ})\). The sin of 90 degrees is 1, so this simplifies to \(\tau = 1.4 \times 10^{-26} \mathrm{A} \cdot \mathrm{m}^{2} \times 1.2 \mathrm{T}\).
04

Compute the final Value

Multiplying these values together gives a final torque of \(1.68 \times 10^{-26} \mathrm{N} \cdot \mathrm{m}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Moment
The magnetic moment, often denoted as \(\boldsymbol{\mu}\), is a vector quantity that represents the magnetic strength and orientation of a magnet or other object producing a magnetic field. Think of it as a measure of the tendency of an object to align with a magnetic field. For charged particles, like protons, this magnetic moment arises from the spin and orbital motions of the charges. Specifically, a proton's spin gives it a characteristic magnetic moment, which is essential for understanding how it interacts with magnetic fields.

In the case of a proton, its magnetic moment can be likened to a tiny bar magnet with a north and south pole. When a magnetic field is applied, it will exert a force on the proton's north and south poles, causing it to experience a torque or twisting force, which we'll discuss further in the section about the torque equation. A key factor to emphasize is that the magnetic moment is intrinsic to the proton and does not change unless the internal structure of the proton is altered.
Torque Equation
Torque in the context of magnetic fields can be a bit abstract, but it's essentially the rotational equivalent of force. It's what happens to a magnetic moment when exposed to a magnetic field. The torque equation for a magnetic moment \(\boldsymbol{\mu}\) in a magnetic field \(\boldsymbol{B}\) is \(\tau = \boldsymbol{\mu} \times \boldsymbol{B}\), with the cross-product indicating that the torque vector is perpendicular to both the magnetic moment and the field.

When the angle \(\theta\) between the magnetic moment and the magnetic field is specifically \(90^\circ\), the situation becomes simpler. This is because \(\sin(90^\circ) = 1\), and the torque equation reduces to \(\tau = \mu B\). The magnitude of the torque is maximized at this angle, leading to the strongest twisting effect on the proton. Understanding this relationship is crucial, as it highlights the interconnectedness between the orientation of the magnetic moment and the resulting torque.
Magnetic Field
A magnetic field, symbolized by \(\boldsymbol{B}\), is a vector field that permeates space where a magnetic force is experienced. It can be visualized as field lines emanating from north poles and terminating at south poles of magnets. This field not only affects materials that are inherently magnetic but also can influence charged particles moving within it.

A key characteristic of magnetic fields is that their influence is directional, which explains why a magnetic moment experiences the greatest torque when perpendicular to the field. When considering fields in a classroom or laboratory setting, it's often uniform and represented by uniform, parallel lines, which simplifies calculations. In our proton example, the magnetic field strength of \(1.2 \mathrm{T}\) represents a fairly strong magnetic field, which would exert a significant torque on a magnetic moment aligned within it, like the proton's.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Some consumer groups urge pregnant women not to use electric blankets, in case there is a health risk from the magnetic fields from the approximately 1 A current in the heater wires. a. Estimate, stating any assumptions you make, the magnetic field strength a fetus might experience. What percentage of the earth's magnetic field is this? b. It is becoming standard practice to make electric blankets with minimal external magnetic field. Each wire is paired with another wire that carries current in the opposite direction. How does this reduce the external magnetic field?

A 1.0 -m-long, 1.0 -mm-diameter copper wire carries a current of \(50.0 \mathrm{A}\) to the east. Suppose we create a magnetic field that produces an upward force on the wire exactly equal in magnitude to the wire's weight, causing the wire to "levitate." What are the field's direction and magnitude?

The magnetic field at the center of a \(1.0-\mathrm{cm}\) -diameter loop is \(2.5 \mathrm{mT}\) a. What is the current in the loop? b. A long, straight wire carries the same current you found in part a. At what distance from the wire is the magnetic field \(2.5 \mathrm{mT} ?\)

Internal components of cathode-ray-tube televisions and computer monitors can become magnetized; the resulting magnetic field can deflect the electron beam and distort the colors on the screen. Demagnetization can be accomplished with a coil of wire whose current switches direction rapidly and gradually decreases in amplitude. Explain what effect this will have on the magnetic moments of the magnetic materials in the device, and how this might eliminate any magnetic ordering.

The magnetic field of the brain has been measured to be approximately \(3.0 \times 10^{-12} \mathrm{T} .\) Although the currents that cause this field are quite complicated, we can get a rough estimate of their size by modeling them as a single circular current loop \(16 \mathrm{cm}\) (the width of a typical head) in diameter. What current is needed to produce such a field at the center of the loop?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.