/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 II A square current loop \(5.0 \... [FREE SOLUTION] | 91Ó°ÊÓ

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II A square current loop \(5.0 \mathrm{cm}\) on each side carries a \(500 \mathrm{mA}\) current. The loop is in a \(1.2 \mathrm{T}\) uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is \(30^{\circ}\) away from the field direction. What is the magnitude of the torque on the current loop?

Short Answer

Expert verified
The magnitude of the torque on the current loop is \(0.00075 N.m\).

Step by step solution

01

Convert all quantities to correct units.

The current \(I\) is given in milliamps, so convert it into Amps: \[I = 500 mA = 0.5 A\]. Moreover, the side length of the square loop is given in cm, so convert it into meters for consistency: \(5.0 cm = 0.05 m\). Note that the magnetic field strength is already in the correct unit (Tesla).
02

Calculate the area of the loop.

Given that the current loop is square and we are given one side, the area \(A\) of the loop can be calculated by squaring the side of the loop: \[A = l^2 = (0.05 m)^2 = 0.0025 m^2\].
03

Calculate the Torque.

We can now calculate the torque \(\tau\) using the formula \(\tau = nIA\sin(\theta)B\). Remember the angle should be in radians, so convert it before substituting into the formula. For this problem: \[\tau = (1)(0.5 A)(0.0025 m^2) \sin(30^{\circ}) (1.2 T) = 0.00075 N.m\]. Remember to keep the answer in the correct unit for torque, which is Newton-meters (N.m).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
The concept of a magnetic field is central to understanding how forces act on moving charges or currents. A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. Imagine invisible lines that spread out from a magnet or an electric current; these lines represent the magnetic field. The strength of the magnetic field is measured in Tesla (T), which indicates the force the field exerts on a moving charge or a current.

In the context of the exercise involving a square current loop, the magnetic field can be envisioned as a series of parallel lines influencing the loop. The field has both a direction, which determines the way magnetic forces will act on the loop, and a magnitude, represented by 1.2 T in this problem. The influence of the field strength is evident when calculating the torque experienced by the current loop, as the torque depends linearly on the strength of the magnetic field.
Right-Hand Rule
The right-hand rule is a useful mnemonic for understanding the direction of a force or a field in physics, particularly in electromagnetism. This rule helps visualize the relationship between current direction, magnetic field, and force direction. When a current-carrying conductor is placed in a magnetic field, it experiences a force. To determine the direction of this force with the right-hand rule, point your thumb in the direction of the current, and let your fingers represent the magnetic field lines. The direction in which your palm pushes signifies the force acting on the conductor.

In our exercise, this rule is crucial for predicting the direction of the electromagnetic torque. Let's imagine following the right-hand rule with the current loop; point your thumb in the direction of the conventional current, and let your fingers curve along the direction of the magnetic field. The resulting torque direction points outwards from the center of the palm. Understanding the rule helps to not only solve problems involving torque and force but also to internalize the three-dimensional nature of electromagnetic interactions.
Electromagnetic Torque
Electromagnetic torque is a fundamental concept when studying the interaction between electric currents and magnetic fields. It refers to the torque exerted on a current loop by a magnetic field, often resulting in rotational motion, as seen in electric motors and generators. The formula for calculating torque on a current loop in a magnetic field is \[\begin{equation} \tau = nIA\sin(\theta)B \end{equation}\], where \(\tau\) is the torque, \(n\) is the number of turns in the loop, \(I\) is the current, \(A\) is the area of the loop, \(\theta\) is the angle between the magnetic field and the normal to the plane of the loop, and \(B\) is the magnetic field strength.

In the solution steps provided, we observe the application of this concept. The calculated torque is dependent on the current, the area of the loop, the strength of the magnetic field, and the sine of the angle between the loop and the field. The calculated torque of 0.00075 N.m illustrates the resultant force trying to rotate the loop, which is crucial for understanding motor functioning and the conversion of electrical to mechanical energy. Moreover, it's important to note that the torque is highest when the plane of the loop is perpendicular to the magnetic field (i.e., when \(\theta = 90^\circ\)) and zero when the plane of the loop is parallel to the field (i.e., when \(\theta = 0^\circ\)).

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Most popular questions from this chapter

A researcher would like to perform an experiment in zero magnetic field, which means that the field of the earth must be canceled. Suppose the experiment is done inside a solenoid of diameter \(1.0 \mathrm{m},\) length \(4.0 \mathrm{m},\) with a total of 5000 turns of wire. The solenoid is oriented to produce a field that opposes and exactly cancels the \(52 \mu\) T local value of the earth's field. What current is needed in the solenoid's wire?

The magnetic field of the brain has been measured to be approximately \(3.0 \times 10^{-12} \mathrm{T} .\) Although the currents that cause this field are quite complicated, we can get a rough estimate of their size by modeling them as a single circular current loop \(16 \mathrm{cm}\) (the width of a typical head) in diameter. What current is needed to produce such a field at the center of the loop?

An electromagnetic flow meter applies a magnetic field of \(0.20 \mathrm{T}\) to blood flowing through a coronary artery at a speed of \(15 \mathrm{cm} / \mathrm{s} .\) What force is felt by a chlorine ion with a single negative charge?

All ferromagnetic materials have a Curie temperature, a temperature above which they will cease to be magnetic. Explain in some detail why you might expect this to be so.

The unit of current, the ampere, is defined in terms of the force between currents. If two 1.0 -meter-long sections of very long wires a distance \(1.0 \mathrm{m}\) apart each carry a current of \(1.0 \mathrm{A}\), what is the force between them? (If the force between two actual wires has this value, the current is defined to be exactly 1 A.)

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