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To what potential should you charge a \(1.0 \mu \mathrm{F}\) capacitor to store \(1.0 \mathrm{J}\) of energy?

Short Answer

Expert verified
The potential to which a \(1.0 \mu \mathrm{F}\) capacitor should be charged to store \(1.0 \mathrm{J}\) of energy is approximately \(1414.21 \mathrm{V}\).

Step by step solution

01

Identify Given Values

From the question, the capacitance \(C\) of the capacitor is given as \(1.0 \mu \mathrm{F}\) (or \(1.0 \times 10^{-6} \mathrm{F}\)) and the energy \(E\) to be stored in the capacitor is given as \(1.0 \mathrm{J}\).
02

Apply the Energy-Capacitance-Potential Relation

We need to rearrange the formula to find the potential difference \(V\). That results in \(V = \sqrt{\frac{2E}{C}}\).
03

Substitute Known Values into the Equation

Substituting the given values into the equation gives \(V = \sqrt{\frac{2 \times 1.0 \mathrm{J}}{1.0 \times 10^{-6} \mathrm{F}}}\).
04

Solve the Equation

Calculate the right-hand side of the equation to get the desired potential difference \(V = 1414.21 \mathrm{V}\).

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Most popular questions from this chapter

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