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A proton with an initial speed of \(800,000 \mathrm{m} / \mathrm{s}\) is brought to rest by an electric field. a. Did the proton move into a region of higher potential or lower potential? b. What was the potential difference that stopped the proton? c. What was the initial kinetic energy of the proton, in electron Volts?

Short Answer

Expert verified
a. The proton moves into a region of higher potential. b. The potential difference can be calculated using the initial kinetic energy and the charge of the proton following the given instructions. c. The initial kinetic energy of the proton can be calculated using \(1/2mv^2\), then converted to eV using the conversion factor.

Step by step solution

01

Determine Direction of Potential Change

Electrical potential energy and electrical potential are related by the equation \( PE = QV \), where PE is the electrical potential energy, Q is the charge and V is the potential (or potential difference). A proton moving from where it initially has kinetic energy and eventually comes to rest must have done work against the electric field. Therefore, it must have moved in the direction of increasing electric potential. Hence, the proton moved into a region of higher potential.
02

Calculate Potential Difference

The proton was initially moving but was brought to rest. This implies that its final kinetic energy is 0. The initial kinetic energy of the proton was given by \( K = 1/2 mv^2 \), where m is the mass of a proton (about \(1.67 x 10^{-27}kg\)) and v is the velocity (\( 800,000 ms^{-1}\)). Using conservation of energy, which states that energy cannot be created or destroyed only transformed, the loss in kinetic energy becomes an increase in electric potential energy. Therefore, the electric potential (V) that the proton moved into is calculated by the equation \( V = PE/Q = mv^2/2Q \), where Q is the charge of a proton (\(1.602 x 10^{-19}C\)). When calculating, units need to be consistent, so velocity should be in m/s and the mass should be in kg.
03

Convert to Electron Volts

After calculating the initial kinetic energy of the proton in Joules, this needs to be converted to electron volts (eV). This is done by using the conversion factor \( 1J = 6.242 x 10^{18} eV \). Multiply the initial kinetic energy of the proton in joules by this conversion factor to obtain the energy in electron volts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Potential Difference
Electric potential difference, also known as voltage, is a fundamental concept in the study of electricity. It is a measure of the work done to move a charge from one point to another against an electric field and is expressed in volts (V). In simpler terms, it represents the energy that a charge would gain or lose when moving between two different points in the presence of an electric field.

Let's think of it like rolling a ball uphill. Just as it takes effort to push the ball up the slope (which increases its potential energy), a proton moving against the direction of an electric field requires work, which increases its electric potential. In the case of our exercise, the proton moves to a region of higher potential, implying it has done work against the field and gained potential energy, corresponding to the work done on it by the external force to bring it to rest.
Kinetic Energy of a Proton
Kinetic energy is the energy that an object possesses due to its motion. For a proton, or any particle, its kinetic energy can be calculated using the classic physics formula \( K = \frac{1}{2} mv^2 \), where \(m\) is the mass of the proton and \(v\) its velocity. The proton in our exercise has a known initial speed and mass, allowing us to calculate its initial kinetic energy.

The concept is akin to a car driving down a road; the faster the car goes, the more kinetic energy it has. When the car comes to a stop, that kinetic energy is converted into other forms of energy, such as heat. Similarly, when the proton comes to rest due to the electric field, its kinetic energy is converted into electric potential energy.
Conservation of Energy in Electric Fields
The principle of conservation of energy tells us that energy cannot be created or destroyed; it can only be transformed from one form into another. This fundamental principle applies to all physical processes, including the motion of charges in electric fields.

In the context of our proton, its initial kinetic energy is transformed entirely into electric potential energy as it comes to rest. This transformation showcases energy conservation: the proton's kinetic energy hasn't disappeared; it's merely taken on a new form. Understanding this concept can be made easier by likening it to a battery-powered toy. As the battery runs out (loss of electric potential energy), the toy slows down and eventually stops moving (loss of kinetic energy), but the energy has merely been transformed into sound, light, or heat.
Electron Volt Conversion
An electron volt (eV) is a unit of energy that's particularly convenient when dealing with the energies of particles at the atomic and subatomic scales. It's defined as the amount of energy an electron (or any charge equal to that of an electron) gains or loses when it moves through an electric potential difference of one volt.

To convert the energy of our proton from joules to electron volts, we use the conversion factor \(1J = 6.242 \times 10^{18} eV\). This conversion is essential because the numbers involved are more manageable and the unit is more relevant for discussions of atomic and particle physics. Imagine you're working with very tiny beads—instead of describing their quantity in truckloads, you'd use a unit that makes practical sense for counting small, discrete items, like 'bead-counts'. This is what the electron volt does for particle energies.

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