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Small frogs that are good jumpers are capable of remarkable accelerations. One species reaches a takeoff speed of \(3.7 \mathrm{m} / \mathrm{s}\) in \(60 \mathrm{ms} .\) What is the frog's acceleration during the jump?

Short Answer

Expert verified
The frog's acceleration during the jump is \(61.67 \, \mathrm{m/s^2}\).

Step by step solution

01

Analysis of given data

Take note of the given data: final velocity (\(v_f\)) is \(3.7 \mathrm{m/s}\), initial velocity (\(v_i\)) as the frog starts from rest is \(0 \mathrm{m/s}\), and the time (\(t\)) over which this occurs is \(60 \mathrm{ms}\) or \(0.060 \mathrm{s}\) when converted to standard units (seconds).
02

Application of acceleration formula

Apply the formula for acceleration which is \(a = \frac{\Delta v}{\Delta t}\). Here, \(\Delta v = v_f - v_i = 3.7ms^{-1} - 0ms^{-1} = 3.7ms^{-1}\) and \(\Delta t = 0.060s\).
03

Calculation

Substitute the known values into the formula and solve for \(a\): \(a = \frac{3.7ms^{-1}}{0.060s} = 61.67ms^{-2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of physics that deals with the motion of objects without considering the forces that cause the motion. It focuses on concepts such as displacement, velocity, and acceleration. When solving physics problems involving motion, it's essential to understand that these quantities are vector quantities, which means they have both magnitude and direction.

Motion Equations
In kinematics, the motion of an object can be described using equations known as motion equations or equations of motion. These equations relate displacement, initial velocity, final velocity, acceleration, and time. The most straightforward equation for acceleration is given by the formula \( a = \frac{\Delta v}{\Delta t} \), where \( \Delta v \) is the change in velocity and \( \Delta t \) represents the change in time.

For objects starting from rest, the initial velocity (\( v_i \)) is zero, making the calculation of acceleration simpler, since the change in velocity is then equal to the final velocity (\( v_f \)). In the example of the jumping frog, the initial velocity is absent and the acceleration is calculated simply by dividing the takeoff velocity by the time taken to reach that velocity.
Physics Problem Solving
Physics problem solving often involves a structured approach to correctly identify and apply relevant concepts and mathematical formulas. Following a step-by-step method can greatly assist with this process. Step 1 usually entails the analysis of the given data and identifying the proper formulas needed. Step 2 involves applying those formulas to the problem at hand. Lastly, Step 3 is the actual calculation where the known values are substituted into the equations to solve for the unknown variable.

In the context of our frog example, by recognizing that the frog's acceleration can be calculated using the simple motion equation provides clarity. It's crucial to convert all units into their standard forms (e.g., milliseconds to seconds) to avoid mistakes and ensure an accurate calculation. A thorough and methodical problem-solving approach not only yields the correct answer but also helps in understanding the concept behind the calculation.

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Most popular questions from this chapter

You are driving to the grocery store at \(20 \mathrm{m} / \mathrm{s}\). You are 110 \(\mathrm{m}\) from an intersection when the traffic light turns red. Assume that your reaction time is \(0.70 \mathrm{s}\) and that your car brakes with constant acceleration. a. How far are you from the intersection when you begin to apply the brakes? b. What acceleration will bring you to rest right at the intersection? c. How long does it take you to stop?

A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.0 s later. What was the rocket's acceleration?

The minimum stopping distance for a car traveling at a speed of \(30 \mathrm{m} / \mathrm{s}\) is \(60 \mathrm{m},\) including the distance traveled during the driver's reaction time of \(0.50 \mathrm{s}\). a. Draw a position-versus-time graph for the motion of the car. Assume the car is at \(x_{i}=0 \mathrm{m}\) when the driver first sees the emergency situation ahead that calls for a rapid halt. b. What is the minimum stopping distance for the same car traveling at a speed of \(40 \mathrm{m} / \mathrm{s} ?\)

A football is kicked straight up into the air; it hits the ground 5.2 s later. a. What was the greatest height reached by the ball? Assume it is kicked from ground level. b. With what speed did it leave the kicker"s foot?

While running a marathon, a long-distance runner uses a stopwatch to time herself over a distance of \(100 \mathrm{m}\). She finds that she runs this distance in 18 s. Answer the following by considering ratios, without computing her velocity. a. If she maintains her speed, how much time will it take her to run the next \(400 \mathrm{m} ?\) b. How long will it take her to run a mile at this speed?

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