/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 In college softball, the distanc... [FREE SOLUTION] | 91Ó°ÊÓ

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In college softball, the distance from the pitcher's mound to the batter is 43 feet. If the ball leaves the bat at \(100 \mathrm{mph}\), how much time elapses between the hit and the ball reaching the pitcher?

Short Answer

Expert verified
The time it takes for the ball to travel from the batter to the pitcher is approximately 0.293 seconds.

Step by step solution

01

Convert speed to feet per second

Since the distance is given in feet while the speed is given in miles per hour, we first convert the speed from miles per hour to feet per second. We know that 1 mile is 5280 feet and 1 hour is 3600 seconds. So, the conversion factor for mph to fps is \((5280/3600)\). By multiplying this conversion factor with the speed, we get \(100 \times (5280/3600) = 146.67 \mathrm{fps}\)
02

Apply the formula for time

We know speed equals distance over time (speed = distance/time), so we can rearrange this formula to solve for time: time = distance / speed. Plugging in our values, we get: time = 43 feet / 146.67 fps = 0.293 seconds
03

Interpret the results

Therefore, it will take about 0.293 seconds for the ball to travel from the batter to the pitcher.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Converting Units of Speed
Converting units of speed is crucial in physics problems because we often encounter different measurement systems. For example, in the United States, speeds are typically measured in miles per hour (mph), while scientists and most other countries use meters per second (m/s). Knowing how to convert between these units allows for consistent measurements and comparisons.

Let's see how this works using the problem from our exercise. To convert the speed from mph to feet per second (fps), we use the relationship that 1 mile equals 5280 feet and 1 hour equals 3600 seconds. The conversion factor is therefore \( 5280 \text{ feet} / 3600 \text{ seconds} \), or approximately \(1.467 \text{ fps}\) for every \(1 \text{ mph}\). So, a ball traveling at \(100 \text{ mph}\) is moving at \(100 \times 1.467 \text{ fps} = 146.7 \text{ fps}\), after rounding to the nearest tenth.

Understanding this process enables students to approach a wider array of problems that involve converting speed units, whether it's for physics experiments, engineering applications, or simply comparing speeds in different countries or situations.
Speed, Distance, and Time Relationship
The relationship between speed, distance, and time is one of the foundational concepts in kinematics. In simple terms, speed tells us how fast an object is moving, distance indicates how far it has gone, and time reveals how long it took to get there. These three quantities are connected by a straightforward equation: \( \text{speed} = \frac{\text{distance}}{\text{time}} \).

For our softball scenario, we are given the distance (\(43 \text{ feet}\)) and the converted speed (\(146.7 \text{ fps}\)). We need to find out the time it takes for the softball to travel from the bat to the pitcher. Rearranging the speed equation gives us \( \text{time} = \frac{\text{distance}}{\text{speed}} \). This yields \( \text{time} = \frac{43}{146.7} \), resulting in approximately \(0.293 \text{ seconds}\) after rounding.

With this relationship, students can solve for any unknown variable as long as the other two are known, which is incredibly helpful for numerous practical problems in physics. It's like solving a puzzle where knowing how pieces fit together gives us the complete picture.
Problem-Solving in Physics
Problem-solving in physics involves applying scientific principles, mathematical formulas, and logical reasoning to find solutions to questions about the natural world. A solid approach to problem-solving includes several key steps: understanding the problem, planning a solution strategy, carrying out the calculations, and then interpreting and evaluating the results.

In our example of the college softball problem, we first understood the task: calculate the time it takes for a ball to reach the pitcher from the batter. Then, we planned our strategy, which included converting units and applying the speed-distance-time relationship. Next, we did the math, which involved converting the speed of the ball to a compatible unit and calculating the time using the rearranged speed formula. Finally, we interpreted the results: it takes approximately \(0.293 \text{ seconds}\) for the ball to reach the pitcher.

To enhance these problem-solving skills, it's beneficial for students to practice with varied exercises, review concepts regularly, and learn from any mistakes. This iterative process helps deepen their conceptual understanding and sharpens their ability to tackle new and more complex problems in the future.

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Most popular questions from this chapter

A simple model for a person running the \(100 \mathrm{m}\) dash is to assume the sprinter runs with constant acceleration until reaching top speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of \(11.2 \mathrm{m} / \mathrm{s}\) in \(2.14 \mathrm{s}\), what will be his total time?

Small frogs that are good jumpers are capable of remarkable accelerations. One species reaches a takeoff speed of \(3.7 \mathrm{m} / \mathrm{s}\) in \(60 \mathrm{ms} .\) What is the frog's acceleration during the jump?

A rock climber stands on top of a \(50-\mathrm{m}\) -high cliff overhanging a pool of water. He throws two stones vertically downward \(1.0 \mathrm{s}\) apart and observes that they cause a single splash. The initial speed of the first stone was \(2.0 \mathrm{m} / \mathrm{s}\). a. How long after the release of the first stone does the second stone hit the water? b. What was the initial speed of the second stone? c. What is the speed of each stone as it hits the water?

Upon impact, bicycle helmets compress, thus lowering the potentially dangerous acceleration experienced by the head.A new kind of helmet uses an airbag that deploys from a pouch worn around the In tests, a headform wearing the inflated airbag is dropped onto a rigid platform; the speed just before impact is \(6.0 \mathrm{m} / \mathrm{s}\). Upon impact, the bag compresses its full \(12.0 \mathrm{cm}\) thickness, slowing the headform to rest. What is the acceleration, in \(g\) 's, experienced by the headform? (An acceleration greater than \(60 \mathrm{g}\) is considered especially dangerous.)

Does a real automobile have con-stant acceleration? Measured data for a Porsche 944 Turbo at maximum acceleration are as shown in the table. a. Convert the velocities to \(\mathrm{m} / \mathrm{s},\) then make a graph of velocity versus time. Based on your graph, is the acceleration constant? Explain. b. Estimate how far the car traveled in the first \(10 \mathrm{s}\). c. Draw a smooth curve through the points on your graph, then use your graph to estimate the car"s acceleration at \(2.0 \mathrm{s}\) and \(8.0 \mathrm{s} .\) Give your answer in \(\mathrm{SI}\) units. Hint: Remember that acceleration is the slope of the velocity graph.$$ \begin{array}{cc} \mathbf{t}(\mathrm{s}) & \boldsymbol{v}_{\boldsymbol{x}}(\mathrm{mph}) \\ \hline 0 & 0 \\ 2 & 41 \\ 4 & 66 \\ 6 & 83 \\ 8 & 97 \\ 10 & 110 \\ \hline \end{array} $$

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