/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 An ideal gas is at \(20^{\circ} ... [FREE SOLUTION] | 91Ó°ÊÓ

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An ideal gas is at \(20^{\circ} \mathrm{C}\). If we double the average kinetic energy of the gas atoms, what is the new temperature in \({ }^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
The new temperature of the gas after doubling the kinetic energy is approximately \( 313.15^{\circ} \mathrm{C} \).

Step by step solution

01

Convert temperature from Celsius to Kelvin

The initial temperature is given in degrees Celsius. The formula provided uses Kelvin, therefore the temperature needs to be converted to Kelvin. The conversion formula is \( T(K) = T(°C) + 273.15 \). Thus, the initial temperature \( T1 = 20°C + 273.15 = 293.15 K\).
02

Apply the kinetic theory of gases

According to the kinetic theory, if we double the kinetic energy, the temperature will also double because they are directly proportional. Thus, the new temperature \( T2 \) will be \( T2 = 2 * T1 = 2 * 293.15 = 586.3 K \).
03

Convert back to Celsius

The task requires the answer in degrees Celsius. Convert the new temperature from Kelvin to Celsius using the formula \( T(°C) = T(K) - 273.15 \). Thus, the temperature in Celsius \( T2 = 586.3K - 273.15 = 313.15°C \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is a fundamental principle in the study of gases. It is a simple relationship between four key physical properties of gases: pressure, volume, temperature, and the number of moles of gas. This law is expressed by the equation \( PV = nRT \), where:
  • \( P \) is the pressure in the gas.
  • \( V \) is the volume of the gas.
  • \( n \) is the amount of substance of gas (measured in moles).
  • \( R \) is the ideal gas constant, approximately equal to \( 8.31 \text{ J/(mol·K)} \).
  • \( T \) is the temperature of the gas in Kelvin.
The Ideal Gas Law assumes that gases behave ideally, meaning that the gas particles do not interact with each other, and they occupy negligible space. While real gases exhibit deviations from ideal behavior, the Ideal Gas Law provides a good approximation for many gases under a wide range of conditions.
Understanding this law helps in predicting how a gas will change under varying conditions of pressure, volume, and temperature.
Temperature Conversion
Temperature conversion is an essential part of many scientific calculations. When dealing with gases, temperatures are often converted between Celsius and Kelvin. Kelvin is the temperature scale used in scientific equations because it starts at absolute zero, the lowest possible temperature. The conversion formulas are:
  • From Celsius to Kelvin: \( T(K) = T(°C) + 273.15 \).
  • From Kelvin to Celsius: \( T(°C) = T(K) - 273.15 \).
In the context of gases, always ensure to convert Celsius to Kelvin when plugging temperatures into equations like the Ideal Gas Law or when working with concepts such as kinetic energy. This is necessary because these laws and equations are defined for absolute temperatures, which can only be correctly represented in Kelvin. By understanding and applying these conversions, students can ensure correct calculations and predictions for real-world gas behaviors.
Kinetic Energy
Kinetic energy in the context of gases refers to the energy possessed by gas particles due to their motion. According to the Kinetic Theory of Gases, temperature is a direct measure of the average kinetic energy of the gas molecules. This means:
  • An increase in the temperature of a gas leads to an increase in the average kinetic energy of its particles.
  • Conversely, a decrease in temperature results in less motion and thus lower kinetic energy.
This concept is crucial because it explains how temperature impacts gas behavior. For example, doubling the average kinetic energy of gas particles will double the temperature in Kelvin. This is a direct relationship and helps us understand phenomena such as gas expansion when heated. The direct proportionality makes kinetic energy changes predictable by simply observing temperature changes, which is particularly useful when applying principles like the Ideal Gas Law.

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Most popular questions from this chapter

Some jellyfish can eject stingers with remarkable force and speed. One species does this by building up a 15 MPa gauge pressure that pushes against the base of a \(2.0-\mu \mathrm{m}\) -diameter stylet, forcing it outward. a. What force does the excess pressure exert on the stylet? b. The mass set into motion is a tiny \(1.0 \times 10^{-12} \mathrm{kg} .\) What is the resulting acceleration?

When you stifle a sneeze, you can damage delicate tissues because the pressure of the air that is not allowed to escape may rise by up to \(45 \mathrm{kPa}\). If this extra pressure acts on the inside of your \(8.4-\mathrm{mm}\) -diameter eardrum, what is the outward force?

An expandable cube, initially \(20 \mathrm{cm}\) on each side, contains \(3.0 \mathrm{g}\) of helium at \(20^{\circ} \mathrm{C} .1000 \mathrm{J}\) of heat energy are transferred to this gas. What are (a) the final pressure if the process is at constant volume and (b) the final volume if the process is at constant pressure?

0.10 \(\mathrm{mol}\) of argon gas is admitted to an evacuated \(50 \mathrm{cm}^{3}\) container at \(20^{\circ} \mathrm{C}\). The gas then undergoes heating at constant volume to a temperature of \(300^{\circ} \mathrm{C}\). a. What is the final pressure of the gas? b. Show the process on a \(p V\) diagram. Include a proper scale on both axes.

\(0.10 \mathrm{mol}\) of argon gas is admitted to an evacuated \(50 \mathrm{cm}^{3}\) container at \(20^{\circ} \mathrm{C}\). The gas then undergoes an isobaric heating to a temperature of \(300^{\circ} \mathrm{C}\). a. What is the final volume of the gas? b. Show the process on a \(p V\) diagram. Include a proper scale on both axes.

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