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A box is \(200 \mathrm{cm}\) wide, \(40 \mathrm{cm}\) deep, and \(3.0 \mathrm{cm}\) high. What is its volume in \(\mathrm{m}^{3} ?\)

Short Answer

Expert verified
The volume of the box is 0.024 cubic metres.

Step by step solution

01

Convert dimensions from cm to m

First, convert each dimension from centimetres to metres by dividing by 100. Thus, the width becomes 2.0 m, the depth becomes 0.4 m, and the height becomes 0.03 m.
02

Calculate the volume

Next, calculate the volume by multiplying the width, depth, and height. Volume = width × depth × height = 2.0 m × 0.4 m × 0.03 m = 0.024 m³.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
In the world of physics and many practical applications, it's crucial to work with the right units of measurement. This exercise involves converting units from centimeters to meters. The process is straightforward but fundamental in ensuring precision and clarity in calculations. When we say a box is 200 cm wide, it may be more intuitive in some contexts to express this dimension in meters.

To convert centimeters to meters, remember the conversion factor: 1 meter equals 100 centimeters. Therefore, to convert from centimeters to meters, simply divide the original measurement by 100.
  • For width: 200 cm = \( \frac{200}{100} \) m = 2.0 m
  • For depth: 40 cm = \( \frac{40}{100} \) m = 0.4 m
  • For height: 3.0 cm = \( \frac{3.0}{100} \) m = 0.03 m
These conversions are essential to maintaining consistency in units, especially when calculating volumes, as shown in this exercise.
Measurement in Physics
Measurement in physics is about capturing the essence of physical quantities through numbers and units. In this particular problem, we are dealing with the measurement of volume, which requires knowing the space occupied by an object. By understanding how to measure and convert dimensions, we gain precise control over the calculations we perform.

The dimensions given are length-like measurements (width, depth, height). When converted to SI units (the international system of units), the values become easily integrable into scientific calculations. Using meters instead of centimeters can lead to more straightforward interpretations and calculations, especially when data is part of broader scientific discourse or engineering designs.

Accurate measurement ensures reliable outcomes. When you deal with measurements, understanding the precision and potential margins of error is crucial. Small mistakes in measurement can lead to substantial errors in applications, particularly when values are squared or cubed, as is often seen in volume or area calculations.
Multiplication of Dimensions
Calculating the volume of an object involves multiplying its dimensions. For a rectangular box, this means multiplying its width, depth, and height. When working with standard units of measurement, these calculations provide the volume in cubic units.

In our exercise, the given calculations are straightforward:
  • First, calculate the volume using converted dimensions in meters:
  • Volume = Width × Depth × Height = 2.0 m × 0.4 m × 0.03 m
Multiplying these dimensions gives a volume of 0.024 cubic meters or \( \mathrm{m}^{3} \). This unit, \( \mathrm{m}^{3} \), is a standard SI unit for measuring large volumes of a liquid or the space within an object, and it's universally accepted in scientific communities.

Understanding how multiplication affects dimensional measurements is vital for any physics or engineering task. It not only ensures that the measured space is correct but also aligns with universally accepted measurement practices. This exercise highlights the importance of working systematically with dimensional measurements to find volumes accurately.

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Most popular questions from this chapter

The maximum amount of water an adult in temperate climates can perspire in one hour is typically \(1.8 \mathrm{L}\). However, after several weeks in a tropical climate the body can adapt, increasing the maximum perspiration rate to \(3.5 \mathrm{L} / \mathrm{h}\). At what rate, in watts, is energy being removed when perspiring that rapidly? Assume all of the perspired water evaporates. At body temperature, the heat of vaporization of water is \(L_{\mathrm{v}}=24 \times 10^{5} \mathrm{J} / \mathrm{kg} .\)

A gas is compressed from \(600 \mathrm{cm}^{3}\) to \(200 \mathrm{cm}^{3}\) at a constant pressure of \(400 \mathrm{kPa}\). At the same time, \(100 \mathrm{J}\) of heat energy is transferred out of the gas. What is the change in thermal energy of the gas during this process?

An ideal gas is at \(20^{\circ} \mathrm{C}\). The gas is cooled, reducing the thermal energy by \(10 \% .\) What is the new temperature in \({ }^{\circ} \mathrm{C} ?\)

An often-overlooked consequence of power generation is "thermal pollution" from excess heat deposited in the environment. The heating can be considerable. Here are some typical numbers: A nuclear power plant generates \(1.0 \mathrm{GW}\) of electric power with an operating efficiency of \(35 \% .\) The reactor has a single-pass cooling system; water from a nearby river is brought in, warmed, and returned to the river. When operating at full power, the plant takes in \(90 \mathrm{m}^{3}\) of water per second, comparable to the flow of a small river. If the river water comes in at \(10^{\circ} \mathrm{C},\) at what temperature does it emerge?

How much energy must be removed from a 200 g block of ice to cool it from \(0^{\circ} \mathrm{C}\) to \(-30^{\circ} \mathrm{C} ?\)

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