/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 A football is inflated in the lo... [FREE SOLUTION] | 91Ó°ÊÓ

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A football is inflated in the locker room before the game. The air warms as it is pumped, so it enters the ball at a temperature of \(27^{\circ} \mathrm{C} .\) The ball is inflated to a gauge pressure of 13 psi. The ball is used for play at \(10^{\circ} \mathrm{C}\). Once the ball cools, what is the pressure in the ball? Assume that atmospheric pressure is 14.7 psi.

Short Answer

Expert verified
The pressure in the football, once cooled to \(10^{\circ} C\), is approximately \(11.3 psi\).

Step by step solution

01

Convert the temperatures to Kelvin

First, the temperatures must be converted from degrees Celsius to Kelvin because the ideal gas law requires that temperature must be expressed in absolute terms (Kelvin). To do this, add 273 to each of the temperatures. Therefore, the initial temperature, \(T1\), is \(27 + 273 = 300 K\) and the final temperature, \(T2\), is \(10 + 273 = 283 K\).
02

Convert the initial pressure to absolute pressure

The initial pressure given is a gauge pressure. It needs to be converted to absolute pressure by adding it to the atmospheric pressure. Thus, the initial pressure, \(P1\), is \(13 psi + 14.7 psi = 27.7 psi\).
03

Calculate the final pressure

By applying the ideal gas law —under constant volume and amount of gas— as \(P1/T1=P2/T2\), we can find the final pressure (\(P2\)). Substitute the known values into this formula to solve for \(P2\): \(P2 = P1 * T2 / T1 = 27.7 psi * 283 K / 300 K = 26 psi\).
04

Converting the final pressure to the gauge pressure

Finally, to find the gauge pressure, subtract the atmospheric pressure from the absolute final pressure. That is, \(P2_{gauge} = P2_{absolute} - P_{atmospheric} = 26 psi - 14.7 psi = 11.3 psi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Temperature Conversion
Understanding how to properly convert temperatures is crucial when working with gas laws. The ideal gas law demands the use of absolute temperature, which means we must use the Kelvin scale, not Celsius or Fahrenheit. To convert from degrees Celsius to Kelvin, you add 273.15 to the Celsius temperature. This is because 0 Kelvin (absolute zero) is equivalent to (-273.15° C), the coldest possible temperature where theoretically gases would have no volume and no pressure because their particles would be at rest.Here's an example to make it clear: To convert 27°C to Kelvin, add 273.15, giving you 300.15 K. Always ensure the temperature is in Kelvin before using it in gas law equations to avoid errors in calculations.
Pressure Conversion
Pressure conversion is another necessary step in working with gases. There are different units for measuring pressure, such as atmospheres (atm), Pascals (Pa), and pounds per square inch (psi). In the given problem, we deal with psi and also need to consider atmospheric pressure, which is roughly equivalent to 14.7 psi at sea level.In many problems, you will start with gauge pressure, which is the pressure above atmospheric pressure. To find absolute pressure from gauge pressure in psi, you simply add the atmospheric pressure to it. For our football example, the gauge pressure is 13 psi and the atmospheric pressure is 14.7 psi, making the absolute pressure 27.7 psi. When the problem asks for the final gauge pressure, you'll do the reverse and subtract atmospheric pressure from the absolute pressure calculated.
Gas Laws in Physics
Gas laws describe the behavior of gases under various conditions of temperature, pressure, and volume. The most fundamental of these is the ideal gas law, represented by the equation PV = nRT, where P denotes the pressure, V is the volume, n is the amount of substance in moles, R is the ideal gas constant, and T is the temperature in Kelvin. The ideal gas law is derived from empirical observations and assumes that gases consist of a large number of tiny particles moving in random motion without any intermolecular forces except during collisions.In the exercise provided, the law is used under the assumption of constant volume and amount of gas, leading to the relation (P1/T1 = P2/T2) that lets us calculate the change in pressure when temperature changes. This relationship is especially useful when analyzing situations where the gas does not change its quantity or volume, such as the air within the football.
Properties of Gases
Gases have unique properties that differentiate them from solids and liquids. They can expand to fill their containers, they are compressible, and they have low densities compared to solids and liquids. These properties are explained by the kinetic molecular theory, which states that gas molecules are in constant, random motion, colliding elastically with each other and the walls of their container.This behavior is reflected in the ideal gas law, where temperature reflects the average kinetic energy of the gas particles. When temperature increases, so does the kinetic energy, resulting in increased pressure if the volume is kept constant. Likewise, when the gas cools as in the football scenario, the kinetic energy of the particles decreases and with it the pressure, assuming the number of gas molecules remains constant.

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Most popular questions from this chapter

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