/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 What is the period of revolution... [FREE SOLUTION] | 91Ó°ÊÓ

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What is the period of revolution of a satellite with mass \(m\) that orbits the earth in a circular path of radius 7880 \(\mathrm{km}\) (about 1500 \(\mathrm{km}\) above the surface of the earth \() ?\)

Short Answer

Expert verified
The period of revolution is approximately 105.6 minutes.

Step by step solution

01

Understanding the Given Facts

We are given the mass of the satellite, a circular orbit with a radius of 7880 km, and that it is orbiting the Earth. The value we are looking for is the period of revolution, which is the time it takes for the satellite to make one complete orbit around the Earth.
02

Using the Formula for Circular Orbits

The period of a satellite orbiting a central body, such as the Earth, in a circular orbit is given by the formula: \[ T = 2\pi \sqrt{\frac{r^3}{GM}} \]where \( r \) is the orbital radius, \( G \) is the gravitational constant \( 6.674 \times 10^{-11} \mathrm{Nm}^2/\mathrm{kg}^2 \), and \( M \) is the mass of the Earth \( 5.972 \times 10^{24} \mathrm{kg} \).
03

Plugging the Values into the Formula

Substitute the values into the formula: \[ T = 2\pi \sqrt{\frac{(7880 \times 10^3)^3}{6.674 \times 10^{-11} \times 5.972 \times 10^{24}}} \]
04

Calculating the Result

Perform the calculations for the expression inside the square root and then compute the period:1. Calculate \( 7880 \times 10^3 \) to convert km to m.2. Cube the value.3. Multiply \( 6.674 \times 10^{-11} \) with \( 5.972 \times 10^{24} \).4. Divide the cube result by the product of the constant multiplication.5. Take the square root of the result.6. Multiply by \( 2\pi \).
05

Final Result Interpretation

After calculations, you will find that the period \( T \) comes out to be approximately 6334 seconds. Convert this into minutes for practical understanding, which will be about 105.6 minutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Orbital Mechanics
Orbital mechanics is a branch of physics focusing on the motion of objects in space under the influence of gravity. It is essential for understanding how satellites move in their orbits around celestial bodies such as Earth. The primary focus is on how gravity keeps these satellites in a consistent path, allowing humans to predict satellite locations and functions over time.
When we talk about satellites, whether natural like moons or artificial ones used for communication and weather forecasting, their paths are determined by gravitational forces. These forces result from the massive pulls from the Earth, the Sun, and other bodies, which require accurate calculations in orbital mechanics to ensure precise satellite deployment and operation.
The fundamental concepts of orbital mechanics help us understand the period of revolution, eccentricity, and velocity of these satellites. Calculating each aspect allows scientists to send satellites on specific missions efficiently.
Gravitational Constant
The gravitational constant, symbolized with a capital "G," is an essential factor in the law of universal gravitation. It quantifies the strength of gravity between two masses. Its value is approximately \( 6.674 imes 10^{-11} ext{Nm}^2/ ext{kg}^2 \). This constant is crucial when computing gravitational forces in scientific calculations and technological applications, such as creating orbits for satellites.
In our particular problem about satellite periods, "G" plays a vital role in deriving the period of revolution around Earth. By combining it with the mass of the Earth and the distance from the satellite to the Earth's center, we establish the central force that governs the satellite's motion. The gravitational constant ensures our calculations agree with the physical universe's laws, making it indispensable in physics and mechanics.
Circular Orbit Formula
The circular orbit formula is a specific equation used to determine the period of an object moving in a circular path around a celestial body, like a satellite around Earth. The formula is expressed as \[ T = 2\pi \sqrt{\frac{r^3}{GM}} \]where:
  • \( T \) is the orbital period,
  • \( r \) is the radius of the orbit,
  • \( G \) is the gravitational constant,
  • \( M \) is the mass of the central body, in this case, Earth.

This formula derives from equating gravitational force with the necessary centripetal force a satellite requires to maintain a circular orbit. It allows us to calculate the time it takes a satellite to complete one full orbit, providing insights into its motion and ensuring we can track its course accurately. Using this formula is crucial for designing satellite orbits that are consistent and predictably secure.
Satellite Motion Equations
Satellite motion equations, like the one used here, provide the mathematical framework needed to predict the paths and actions of satellites. These equations adapt Newtonian physics principles to the scale and environment of space, accounting for aspects such as gravitational pulls and satellite speed.
Through formulas like the one we have, which incorporates gravitational constants and orbital radii, we can:
  • Determine orbital periods and other key characteristics,
  • Evaluate the stability of orbits,
  • Ensure safe spaceship and satellite launches.

By using equations adapted to space conditions, scientists and engineers are capable of designing efficient missions and deploying satellites in very precise orbits. This capability is essential for purposes like global communication, climate monitoring, and scientific research, enabling technology applications that impact daily life globally.

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Most popular questions from this chapter

Stay dry! You tie a cord to a pail of water, and you swing the pail in a vertical circle of radius 0.600 \(\mathrm{m} .\) What minimum speed must you give the pail at the highest point of the circle if no water is to spill from it? Start with a free-body diagram of the water at its highest point.

A small button placed on a horizontal rotating platform with diameter 0.320 \(\mathrm{m}\) will revolve with the plattorm when it is brought up to a speed of 40.0 \(\mathrm{rev} / \mathrm{min}\) , provided the button is no more than 0.150 \(\mathrm{m}\) from the axis. (a) What is the coefficient of static friction between the button and the platform? (b) How far from the axis can the button be placed, without slipping, if the platform rotates at 60.0 rev/min?

As your bus rounds a flat curve at constant speed, a package with mass \(0.500 \mathrm{kg},\) suspended from the luggage compartment of the bus by a string 45.0 \(\mathrm{cm}\) long, is found to hang at rest relative to the bus, with the string making an angle of \(30.0^{\circ}\) with the vertical. In this position, the package is 50.0 \(\mathrm{m}\) from the center of curvature of the curve. What is the speed of the bus?

A highway curve with radius 900.0 \(\mathrm{ft}\) is to be banked so that a car traveling 55.0 mph will not skid sideways even in the absence of friction. (a) Make a free-body diagram of this car. (b) At what angle should the curve be banked?

Artificial gravity in space stations. One problem for humans living in outer space is that they are apparently weight- less. One way around this problem is to design a cylindrical space station that spins about an axis through its center at a constant rate. (See Figure \(6.32 . )\) This spin creates "artificial gravity" at the outside rim of the station. (a) If the diameter of the space station is \(800.0 \mathrm{m},\) how fast must the rim be moving in order for the "artificial gravity" acceleration to be \(g\) at the outer rim? (b) If the space station is a waiting area for travelers going to Mars, it might be desirable to simulate the acceleration due to gravity on the Martian surface. How fast must the rim move in this case? (c) Make a free-body diagram of an astronaut at the outer rim.

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