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The asteroid 234 Ida has a mass of about \(4.0 \times 10^{16} \mathrm{kg}\) and an average radius of about 16 \(\mathrm{km}\) (it's not spherical, but you can assume it is). (a) Calculate the acceleration of gravity on 234 Ida. (b) What would an astronaut whose earth weight is 650 \(\mathrm{N}\) weigh on 234 lda? (c) If you dropped a rock from a height of 1.0 \(\mathrm{m}\) on 234 Ida, how long would it take to reach the ground? (d) If you can jump 60 \(\mathrm{cm}\) straight up on earth, how high could you jump on 234 Ida? (Assume the asteroid's gravity doesn't weaken significantly over the distance of your jump.)

Short Answer

Expert verified
(a) \( g \approx 0.279 \, \mathrm{m/s^2} \); (b) \( 18.135 \, \mathrm{N} \); (c) \( 2.68 \, \mathrm{s} \); (d) \( 21.11 \, \mathrm{m} \).

Step by step solution

01

Calculate gravitational acceleration on 234 Ida

To find the acceleration due to gravity on 234 Ida, we use the formula from Newton's law of universal gravitation:\[ g = \frac{G \cdot M}{r^2} \]where \( G \approx 6.674 \times 10^{-11} \mathrm{Nm^2/kg^2} \) is the gravitational constant, \( M = 4.0 \times 10^{16} \mathrm{kg} \) is the mass of the asteroid, and \( r = 16000 \) meters (since 16 km = 16000 m) is its radius.Substituting these values into the formula:\[ g = \frac{6.674 \times 10^{-11} \cdot 4.0 \times 10^{16}}{(16000)^2} \]Calculate to find \( g \simeq 0.279 \mathrm{m/s^2} \).
02

Calculate astronaut weight on 234 Ida

Weight on another celestial body is given by the formula:\[ W' = m \cdot g \]where \( m = \frac{650 ewline/( \mathrm{N} \mathrm{m/s^2}}= 65 \, \mathrm{kg} \) (using Earth's gravity \( g = 9.81 \, \mathrm{m/s^2}\)) is the mass of the astronaut, and \( g \simeq 0.279 \mathrm{m/s^2} \) is the gravity on 234 Ida.Substitute to find the astronaut's weight:\[ W' = 65 \cdot 0.279 \approx 18.135 \, \mathrm{N} \].
03

Calculate time for a rock to fall 1.0m on 234 Ida

Use the equation of motion for the time, \( t \), it takes for an object to fall a certain distance under constant acceleration:\[ s = \frac{1}{2}gt^2 \]Set \( s = 1.0 \, \mathrm{m} \) and solve for \( t \):\[ 1.0 = \frac{1}{2}(0.279)t^2 \]\[ t^2 \approx \frac{1.0 \times 2}{0.279} \]\[ t \approx \sqrt{7.168} \approx 2.68 \, \mathrm{s} \].
04

Calculate jump height on 234 Ida

When jumping, the kinetic energy is converted into potential energy, which is given by the formula:\[ h \cdot g_{\text{Ida}} = h_{\text{Earth}} \cdot g_{\text{Earth}} \]Given that \( h_{\text{Earth}} = 0.60 \, \mathrm{m} \) and \( g_{\text{Earth}} = 9.81 \, \mathrm{m/s^2} \), substitute to find the jump height on 234 Ida:\[ h \cdot 0.279 = 0.60 \times 9.81 \]\[ h \approx \frac{0.60 \times 9.81}{0.279} \approx 21.11 \, \mathrm{m} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's law of universal gravitation
Newton's law of universal gravitation is an essential concept in understanding how gravity operates not just on Earth, but throughout the universe. According to this law, any two masses attract each other with a force that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between their centers. In mathematical terms, this is expressed as:
\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \]
Here:
  • \( F \) is the gravitational force between the two objects,
  • \( G \approx 6.674 \times 10^{-11} \, \mathrm{Nm^2/kg^2} \) is the gravitational constant,
  • \( m_1 \) and \( m_2 \) are the masses of the objects,
  • \( r \) is the distance between the centers of the two objects.

For an asteroid like 234 Ida, which is less massive than Earth, the gravitational pull experienced is weaker, resulting in different gravitational effects for us compared to Earth.
acceleration of gravity
The acceleration of gravity, denoted as \( g \), is the rate at which an object accelerates due to the gravitational force. It's crucial for calculating various phenomena like free-fall or the weight of objects on different planets or asteroids.
On Earth, you might be familiar with the standard gravity value \( g = 9.81 \, \mathrm{m/s^2} \). However, on an asteroid like 234 Ida, gravity is much weaker due to its smaller mass.
Using Newton's formula for gravitational acceleration:
\[ g = \frac{G \cdot M}{r^2} \]
we find that on 234 Ida, \( g \approx 0.279 \, \mathrm{m/s^2} \), meaning objects fall much more slowly compared to Earth. This slower acceleration influences various dynamics, such as how astronauts would weigh differently or how high one could jump on the asteroid.
weight on celestial bodies
Weight is the force exerted by gravity on an object and varies depending on the celestial body one is on. Given by the formula:
\[ W = m \cdot g \]
where \( m \) is the mass of the object and \( g \) is the gravitational acceleration of the celestial body, it helps us understand how gravity affects matter in space.
For instance, an astronaut who weighs 650 N on Earth will weigh significantly less on 234 Ida, due to its weaker gravitational pull. Using the asteroid's gravity, \( g \approx 0.279 \, \mathrm{m/s^2} \), we find the astronaut's weight to be approximately 18.135 N. This illustrates how one's weight can drastically change even though their mass remains constant.
equations of motion
Equations of motion play a crucial role in predicting how objects will move under the influence of gravity. These equations help calculate distances, velocities, and times of travel, especially important in physics and astronomy.
In the exercise, the equation:
\[ s = \frac{1}{2} g t^2 \]
is used to determine how long it takes for an object to fall a certain distance under constant acceleration. When dropping a rock from 1 meter on 234 Ida, we solve for time to get approximately 2.68 seconds. Calculations like these are essential for understanding motion characteristics under different gravitational conditions.
energy conservation in jumps
Energy conservation is a fundamental principle in physics, indicating that energy cannot be created or destroyed, only transformed. When jumping, kinetic energy transforms into potential energy at the peak of the jump.
For comparing how high one can jump on Earth versus an asteroid, we use energy conservation:
\[ h \cdot g_{\text{Ida}} = h_{\text{Earth}} \cdot g_{\text{Earth}} \]
where \( h \) is the height of the jump and \( g \) represents gravitational acceleration. On Earth, a jump of 60 cm translates to a significantly higher jump of around 21.11 meters on 234 Ida, thanks to its lower gravitational pull. This illustrates how conservation laws help predict and compare physical activities across different environments.

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