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\(\bullet\) You measure the length of a futuristic car to be 3.60 \(\mathrm{m}\) when the car is at rest relative to you. If you measure the length of the car as it zooms past you at a speed of \(0.900 c,\) what result do you get?

Short Answer

Expert verified
The contracted length of the car is approximately 1.57 m.

Step by step solution

01

Understand Length Contraction

The phenomenon of length contraction states that the length of an object in motion relative to an observer will be shorter than its length at rest. This effect becomes significant at velocities close to the speed of light, denoted as \(c\). The formula for length contraction is: \(L = L_0 \sqrt{1 - \frac{v^2}{c^2}}\), where \(L\) is the contracted length, \(L_0\) is the proper length (rest length), \(v\) is the relative velocity, and \(c\) is the speed of light.
02

Identify Known Values

From the problem statement, we know the rest length \(L_0 = 3.60\, \text{m}\), and the velocity \(v = 0.900c\). Our task is to find the contracted length \(L\) as the car moves past at this speed.
03

Substitute and Simplify

Substitute all the known values into the length contraction formula: \[ L = 3.60 \sqrt{1 - (0.900)^2} \] First, calculate \(0.900^2 = 0.810\). Then the expression inside the square root becomes \(1 - 0.810 = 0.190\).
04

Calculate the Contracted Length

Now calculate the square root: \( \sqrt{0.190} \approx 0.43589 \). Then multiply by the rest length: \( L = 3.60 \times 0.43589 \approx 1.57 \text{ m} \).
05

Interpret the Result

The length of the futuristic car, as measured when it zooms past at \(0.900c\), is approximately \(1.57\, \text{m}\). This is shorter than the rest length due to the effects of length contraction, which are significant at speeds approaching the speed of light.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relativity
Relativity is a fundamental concept in physics, formulated by Albert Einstein. It proposes that the laws of physics are the same for all non-accelerating observers, no matter their location in the universe. One of the key outcomes of relativity is that time and space are intertwined in a four-dimensional "spacetime" structure.

A particularly interesting aspect of relativity is the impact of movement on the perception of time and space. When an object moves at a significant fraction of the speed of light, its length appears smaller to observers not moving with it. This is called "length contraction". Relativity also suggests that no object with mass can reach, or exceed, the speed of light because it would require infinite energy.

To understand relativistic effects, it's important to think beyond the three-dimensional world we're accustomed to and recognize that our perceptions of time and space can change dramatically at high velocities, though these effects only become noticeable as we approach relativistic speeds.
Speed of Light
The speed of light, denoted as \(c\), is approximately \(299,792,458 \, \text{m/s}\). In the context of relativity, it's crucial to grasp that this is not just a universal speed limit; it's also a constant used in equations that govern how we perceive time and space.

Why is the Speed of Light so Important?

  • It represents the maximum speed at which information or matter can travel in the universe.
  • The unique properties of light speed lead to fascinating phenomena, such as time dilation and length contraction.
  • The constancy of light speed is a cornerstone of Einstein's theory of relativity, affecting not only distance but also how quickly events unfold relative to different observers.
Understanding the speed of light helps clarify why objects appear shortened when moving at speeds close to \(c\), because at that range, length contraction becomes significant.
Length Measurement
Length measurement is not as straightforward at high speeds due to relativistic effects. When an object moves at a significant fraction of light speed, its length appears shorter to a stationary observer than its rest length (the length measured when the object is not moving).

This phenomenon, known as "length contraction", is mathematically expressed as:\[L = L_0 \sqrt{1 - \frac{v^2}{c^2}}\]where:
  • \(L\) is the contracted length,
  • \(L_0\) is the rest length, and
  • \(v\) is the velocity of the object.

In practical terms, as illustrated in the exercise, if a car is 3.60 meters when at rest but then drives past at 0.900 times the speed of light, its measured length decreases to approximately 1.57 meters. This shrinkage is invisible at everyday speeds, becoming observable only at velocities approaching the speed of light.
Physics Problem Solving
Physics problem solving often involves applying theories to specific situations. In this case, we need to understand and utilize the concept of length contraction, a direct outcome of relativistic physics.

Key Steps in Problem Solving:

  • Identify the Principles: Recognize that length contraction due to high speeds near light speed is at play.
  • Understand the Formula: Use \(L = L_0 \sqrt{1 - \frac{v^2}{c^2}}\) to find the contracted length.
  • Determine Known Values: Input the rest length (3.60 meters) and velocity (0.900c) into the formula.
  • Substitute and Solve: Compute the square root and multiply by the original length to find the contracted length.
  • Interpret the Results: Assess whether the outcome makes sense in the context of the problem.
Approaching physics problems with a clear method allows for more intuitive analysis and logical calculation, solidifying both your conceptual understanding and practical skills.

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Most popular questions from this chapter

An antimatter reactor. When a particle meets its antipar- ticle (more about this in Chapter 30 , they annihilate each other and their mass is converted to light energy. The United States uses approximately 1.0 \(\times 10^{20} \mathrm{J}\) of energy per year. (a) If all this energy came from a futuristic antimatter reactor, how much mass would be consumed yearly? (b) If this antimatter fuel had the density of Fe \(\left(7.86 / \mathrm{cm}^{3}\right)\) and were stacked in bricks to form a cubical pile, how high would it be? (Before you get your hopes up, antimatter reactors are a long way in the future-if they ever will be feasible.)

\(\bullet\) Using both the nonrelativistic and relativistic expressions, compute the kinetic energy of an electron and the ratio of the two results (relativistic divided by nonrelativistic), for speeds of (a) \(5.00 \times 10^{7} \mathrm{m} / \mathrm{s},\left(\) b) \(2.60 \times 10^{8} \mathrm{m} / \mathrm{s}\) . \right.

\(\bullet\) A rocket is moving to the right at half the speed of light relative to the earth. A lightbulb in the center of a room inside the rocket suddenly turns on. Call the light hitting the front end of the room event \(A\) and the light hitting the back of the room event \(B\) . (See Figure \(27.23 . )\) Which event occurs first, \(A\) or \(B\) , or are they simultaneous, as viewed by (a) an astronaut riding in the rocket and (b) a person at rest on the earth?

\(\bullet\) (a) Through what potential difference does an electron have to be accelerated, starting from rest, to achieve a speed of 0.980\(c ?\) (b) What is the kinetic energy of the electron at this speed? Express your answer in joules and in electronvolts.

\(\bullet\) Neutron stars are the remains of exploded stars, and they rotate at very high rates of speed. Suppose a certain neutron star has a radius of 10.0 \(\mathrm{km}\) and rotates with a period of 1.80 \(\mathrm{ms}\) . (a) Calculate the surface rotational speed at the equator of the star as a fraction of \(c .\) (b) Assuming the star's surface is an iner- tial frame of reference (which it isn't, because of its rotation), use the Lorentz velocity transformation to calculate the speed of a point on the equator with respect to a point directly oppo- site it on the star's surface.

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