/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 You and a friend start out at th... [FREE SOLUTION] | 91Ó°ÊÓ

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You and a friend start out at the same time on a 10 -km run. Your friend runs at a steady 2.5 \(\mathrm{m} / \mathrm{s} .\) How fast do you have to run if you want to finish the run 15 minutes before your friend?

Short Answer

Expert verified
You need to run at approximately 3.23 m/s.

Step by step solution

01

Convert Units

Your friend's speed is given in meters per second, so first, convert the 10-km run to meters: \[ 10 \text{ km} = 10,000 \text{ m} \].
02

Calculate Friend's Time

Using the formula \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \), calculate the time it takes for your friend to finish:\[ \text{Time} = \frac{10,000 \text{ m}}{2.5 \text{ m/s}} = 4,000 \text{ seconds} \].
03

Calculate Target Time

Since you want to finish 15 minutes (which is 900 seconds) before your friend, subtract 900 seconds from your friend’s time:\[ 4,000 \text{ seconds} - 900 \text{ seconds} = 3,100 \text{ seconds} \].
04

Calculate Required Speed

Using the formula for speed \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \), calculate the speed you need to run:\[ \text{Speed} = \frac{10,000 \text{ m}}{3,100 \text{ seconds}} \approx 3.23 \text{ m/s} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Unit conversion is a vital initial step in problem-solving, especially in physics, where measurements can vary in units. In this particular problem, the aim is to convert the distance of the run from kilometers to meters. A kilometer is equivalent to 1,000 meters, making the conversion straightforward:
  • 1 km = 1,000 m
  • 10 km = 10,000 m
This conversion is crucial because the friend's speed is given in meters per second (m/s), and keeping both distance and speed in consistent units ensures accurate calculations. Always make sure the units you work with are compatible, helping you avoid mistakes and confusion later on in solving any problem.
Time Calculation
To figure out how long a task will take, use the formula for time: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] For your friend running 10,000 meters at a speed of 2.5 meters per second, the time taken can be calculated by:\[ \text{Time} = \frac{10,000 \text{ m}}{2.5 \text{ m/s}} = 4,000 \text{ seconds} \] This calculation means your friend will complete the run in 4,000 seconds. Understanding how to calculate time using the distance and speed enables you to plan your pace and determine total time taken with accuracy. This helps set the stage for comparing different intervals or requirements, like targeting a finishtime ahead of your friend.
Speed Calculation
Speed calculation involves determining how fast you must travel to meet a certain target time or distance goal. To find the required speed for finishing the race earlier than your friend, you first need to establish your target finish time. This involves subtracting the desired lead time from your friend's total time. Your friend's completion time is 4,000 seconds, and you plan to finish 15 minutes earlier. Convert those 15 minutes into seconds:
  • 15 minutes = 15 \( \times \) 60 = 900 seconds
Therefore, your target time is: \[ 4,000 \text{ seconds} - 900 \text{ seconds} = 3,100 \text{ seconds} \] To find out your speed: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{10,000 \text{ m}}{3,100 \text{ seconds}} \approx 3.23 \text{ m/s} \] This shows that to finish on your goal schedule, you'll need to maintain a running speed of approximately 3.23 meters per second. By understanding how to use these calculations, you can adjust your speed based on the time or distance constraints.
Distance and Time Relationship
The relationship between distance and time is a cornerstone concept in physics and daily measurement problems. Generally, this relationship explains that the time it takes to travel a certain distance is influenced by the speed at which you are traveling. In the context of this exercise, realizing that you wish to finish ahead of your friend requires leveraging this fundamental relationship.
  • If speed increases with distance kept constant, the travel time decreases.
  • Conversely, a decrease in speed with distance constant leads to more time taken.
Understanding this interplay allows you to strategize effectively for a scenario where you need to finish earlier, as the speed must compensate for the timespan difference you are targeting. This simple mathematical relation helps clarify and predict travel outcomes, essential for planning or calculating required adjustments in speed or time for a given distance.

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Most popular questions from this chapter

In \(1954,\) Roger Bannister became the first human to run a mile in less than 4 minutes. Suppose that a runner on a straight track covers a distance of 1.00 mi in exactly 4.00 min. What is his average speed in (a) \(\mathrm{mi} / \mathrm{h},\) (b) \(\mathrm{ft} / \mathrm{s},\) and \((\mathrm{c}) \mathrm{m} / \mathrm{s}\) ?

If the radius of a circle of area \(A\) and circumference \(C\) is doubled, find the new area and circumference of the circle in terms of \(A\) and \(C .\) (Consult Chapter 0 if necessary.)

At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constant acceleration of 2.50 \(\mathrm{m} / \mathrm{s}^{2} .\) At the same instant, a truck, traveling with a constant speed of \(15.0 \mathrm{m} / \mathrm{s},\) overtakes and passes the automobile. (a) How far beyond its starting point does the automobile overtake the truck? (b) How fast is the automobile traveling when it overtakes the truck?

Air-bag injuries. During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshield or steering wheel. According to safety standards, the bags produce a maximum acceleration of \(60 \mathrm{g},\) but lasting for only 36 \(\mathrm{ms}\) (or less). How far (in meters) does a person travel in coming to a complete stop in 36 \(\mathrm{ms}\) at a constant acceleration of 60 \(\mathrm{g}\) ?

Plate tectonics. The earth's crust is broken up into a series of more-or-less rigid plates that slide around due to motion of material in the mantle below. Although the speeds of these plates vary somewhat, they are typically about 5 \(\mathrm{cm} / \mathrm{yr.}\) . Assume that this rate remains constant over time. (a) If you and your neighbor live on opposite sides of a plate boundary at which one plate is moving northward at 5.0 \(\mathrm{cm} / \mathrm{yr}\) with respect to the other plate, how far apart do your houses move in a century? (b) Los Angeles is presently 550 \(\mathrm{km}\) south of San Francisco, but is on a plate moving northward relative to San Francisco. If the 5.0 \(\mathrm{cm} / \mathrm{yr}\) velocity continues, how many years will it take before Los Angeles has moved up to San Francisco?

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