/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 (a) The pilot of a jet fighter w... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) The pilot of a jet fighter will black out at an acceleration greater than approximately 5\(g\) if it lasts for more than a few seconds. Express this acceleration in \(\mathrm{m} / \mathrm{s}^{2}\) and \(\mathrm{ft} / \mathrm{s}^{2}\) (b) The acceleration of the passenger during a car crash with an air bag is about 60\(g\) for a very short time. What is this acceleration in \(\mathrm{m} / \mathrm{s}^{2}\) and \(\mathrm{ft} / \mathrm{s}^{2}\) (c) The acceleration of a falling body on our moon is 1.67 \(\mathrm{m} / \mathrm{s}^{2} .\) How many \(g^{\prime}\) is this? (d) If the acceleration of a test plane is \(24.3 \mathrm{m} / \mathrm{s}^{2},\) how many \(g^{\prime}\) is it?

Short Answer

Expert verified
(a) 49 m/s², 161 ft/s². (b) 588 m/s², 1932 ft/s². (c) 0.1704 g. (d) 2.48 g.

Step by step solution

01

Understanding the unit 'g'

The unit 'g' refers to the acceleration due to gravity on Earth, approximately equal to 9.8 meters per second squared (\(9.8 \, \text{m/s}^2\)) or 32.2 feet per second squared (\(32.2 \, \text{ft/s}^2\)). We'll use these conversions for the subsequent calculations.
02

Converting 5g to m/s² and ft/s²

To convert 5g into \(\text{m/s}^2\), multiply 5 by the acceleration due to gravity in \(\text{m/s}^2\):\[5 \times 9.8 \, \text{m/s}^2 = 49 \, \text{m/s}^2.\]To convert 5g into \(\text{ft/s}^2\), multiply 5 by the acceleration due to gravity in \(\text{ft/s}^2\):\[5 \times 32.2 \, \text{ft/s}^2 = 161 \, \text{ft/s}^2.\]
03

Converting 60g to m/s² and ft/s²

To convert 60g into \(\text{m/s}^2\), multiply 60 by the acceleration due to gravity in \(\text{m/s}^2\):\[60 \times 9.8 \, \text{m/s}^2 = 588 \, \text{m/s}^2.\]To convert 60g into \(\text{ft/s}^2\), multiply 60 by the acceleration due to gravity in \(\text{ft/s}^2\):\[60 \times 32.2 \, \text{ft/s}^2 = 1932 \, \text{ft/s}^2.\]
04

Converting moon's acceleration to g

To convert 1.67 \(\text{m/s}^2\) to g, divide by the acceleration due to gravity on Earth:\[\frac{1.67 \, \text{m/s}^2}{9.8 \, \text{m/s}^2} \approx 0.1704 \, g.\]
05

Converting test plane's acceleration to g

To convert 24.3 \(\text{m/s}^2\) to g, divide by the acceleration due to gravity on Earth:\[\frac{24.3 \, \text{m/s}^2}{9.8 \, \text{m/s}^2} \approx 2.48 \, g.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Due to Gravity
Gravity is a force that keeps us anchored to the Earth, and its acceleration is a constant value that we often use in physics problems and calculations. This acceleration, denoted as "g," is what objects experience when they fall freely towards the Earth. On Earth, this acceleration is approximately 9.8 meters per second squared (\(9.8 \, \text{m/s}^2\)).
In the imperial system, which is commonly used in the United States, this value is equal to 32.2 feet per second squared (\(32.2 \, \text{ft/s}^2\)). This constant forms the basis for calculating other accelerations in terms of g-forces, especially when dealing with rapid acceleration scenarios, such as those experienced by athletes or machinery.
Unit Conversion
Converting between units is an essential skill in physics, helping us understand situations from different perspectives. When dealing with acceleration, knowing how to switch between meters per second squared and feet per second squared is crucial. This involves a factor of interchangeability whereby 1 \(\text{m/s}^2\) is equivalent to approximately 3.28084 \(\text{ft/s}^2\).
For example, when a pilot is experiencing a g-force of 5g, you can multiply 5 by the acceleration due to gravity in each system to find the equivalent acceleration, which is essential when detailing the impact on a pilot’s body or a vehicle. These conversions are not just mathematical exercises but are applied for safety and engineering decisions around the world.
  • To convert from \(\text{m/s}^2\) to \(\text{ft/s}^2\), multiply by 3.28084.
  • To convert from \(\text{ft/s}^2\) to \(\text{m/s}^2\), divide by 3.28084.
G-Force
G-force is a measure of acceleration that is compared to the free fall of gravity on Earth. It's commonly used to describe the effects of acceleration on bodies, particularly in vehicles. A g-force of 1g is equal to the acceleration of gravity, or 9.8 \(\text{m/s}^2\).
When a pilot or astronaut experiences high g-forces, their bodies undergo stress that can lead to physical effects like blackouts, which occur when blood moves away from the brain quicker than the heart can pump it back. G-forces are crucial in designing vehicles, as they must safely handle the physical limitations of humans and machinery."
Most importantly, in physics problems, these g-forces help articulate how much acceleration a moving body endures, making it vital to engender systems that keep pilots and passengers safe during rapid accelerations.
Jet Pilot Blackout
Jet pilots experience extreme conditions, one of which is blackout during high-acceleration maneuvers. When the acceleration reaches around 5g, pilots may lose consciousness if subjected to this force for more than a few seconds.
This happens because blood rushes from the brain, causing a loss of oxygen and leading to a temporary loss of vision. Pilots undergo rigorous training and use specially designed pressure suits to withstand these forces, maintaining blood flow to the brain during flight.
By converting the acceleration of 5g into tangible units like \(49 \, \text{m/s}^2\) or \(161 \, \text{ft/s}^2\), engineers can create better safety equipment and plan mission strategies to avoid these risky situations.
Car Crash Acceleration
Car crashes often involve sudden stops with tremendous forces acting on the vehicle and passengers. When considering car crash physics, knowing the potential acceleration is vital for designing safety features such as airbags.
The acceleration during a crash can reach values of 60g, which is extremely high and could be lethal without the intervention of safety mechanisms. In more relatable units, this means an acceleration of \(588 \, \text{m/s}^2\) or approximately \(1932 \, \text{ft/s}^2\) occurs momentarily. Such data inform engineers and automotive designers to create safer vehicles by maximizing survivability from these extreme accelerations.
With these considerations, car manufacturers enhance vehicle structures and incorporate sophisticated restraint systems to minimize injury during accidents.

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