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Lightbulbs in series, I. The power rating of a lightbulb is the power it consumes when connected across a 120 \(\mathrm{V}\) out-let. (a) If you put two 100 \(\mathrm{W}\) bulbs in series across a 120 \(\mathrm{V}\) outlet, how much power would each consume if its resistance were constant? (b) How much power does each one consume if you connect them in parallel across a 120 \(\mathrm{V}\) outlet?

Short Answer

Expert verified
Each bulb consumes 20.83 W in series and 100 W in parallel.

Step by step solution

01

Understanding Bulb Resistance

First, we need to find the resistance of each 100 W bulb when connected to a 120 V outlet. Using the formula for power \(P = \frac{V^2}{R}\) where \(P\) is power, \(V\) is voltage, and \(R\) is resistance, we find \(R\) by rearranging to \(R = \frac{V^2}{P}\). Substituting the given values, \(R = \frac{120^2}{100} = 144\ \Omega\).
02

Power Consumption in Series Connection

When two bulbs are in series, the total resistance \(R_{total}\) is the sum of the individual resistances, so \(R_{total} = 2 \times 144\ \Omega = 288\ \Omega\). The current \(I\) in the series circuit is given by \(I = \frac{V}{R_{total}} = \frac{120}{288} = \frac{5}{12}\ \text{A}\). The power consumed by each bulb is calculated using \(P = I^2 \times R = \left(\frac{5}{12}\right)^2 \times 144 = 20.83\ \text{W}\).
03

Power Consumption in Parallel Connection

In a parallel connection, each bulb gets the full 120 V. The power consumed by each bulb remains \(P = \frac{V^2}{R} = \frac{120^2}{144} = 100\ \text{W}\) as they maintain their full power rating.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Circuits
Series circuits are a common type of circuit configuration where electrical components are connected one after the other in a single path. When components like lightbulbs are arranged in series, the same current flows through each component. However, the total voltage across a series circuit is the sum of the voltages across each component.

- **Key Points about Series Circuits:** - The total resistance is the sum of individual resistances. - A single path for current means that if one component fails, the entire circuit stops working. - Adding more components increases total resistance, reducing the current in the circuit.
For example, if you have two lightbulbs of equal resistance in series, like in the exercise, the overall resistance increases. This reduces the current through the circuit, leading to lower power consumption for each bulb compared to when they are connected individually.
Parallel Circuits
Parallel circuits arrange components side by side, providing multiple paths for the current. Each component in a parallel circuit receives the full voltage of the power source, which allows them to operate independently.

- **Characteristics of Parallel Circuits:** - Total resistance decreases as you add more components because they provide additional paths for current. - Each component experiences the full voltage available, maintaining its individual functionality. - If one component fails, others continue working since they have their own pathways to the power source.
As seen in a practical example, such as the two lightbulbs in parallel, each bulb retains its full power rating since they each receive the full voltage of 120 V. This means both bulbs will consume their rated power of 100 W, functioning as though they are connected separately to the power source.
Resistance Calculation
Calculating resistance is crucial for understanding how circuits function. Resistance is a measure of how much a component resists the flow of current. It's calculated using the formula:

\[ R = \frac{V^2}{P} \]
Where: - \( R \) is resistance - \( V \) is voltage across the component - \( P \) is power consumed by the component
In our exercise, each 100 W lightbulb connected to a 120 V outlet has a resistance of 144 \( \Omega \). This was found by rearranging the power formula to solve for resistance, highlighting how voltage and power affect a device's resistance in an electric circuit.
Power Consumption
Power consumption refers to the rate at which electrical energy is converted into another form of energy, such as heat or light. It is calculated differently depending on how components are arranged in a circuit.

- **Power in Series Circuits:** - Power consumed by a component can be calculated using \( P = I^2 \times R \) where \( I \) is the current through the component and \( R \) is its resistance. - Since the current in a series circuit is reduced due to increased resistance, the power consumption of each individual component is typically less than its standalone rating.
- **Power in Parallel Circuits:** - Each component gets full voltage, so its power consumption remains at its rated value \( P = \frac{V^2}{R} \). - As seen in the example with two lightbulbs, each one consumes 100 W which is its full rated power.
Understanding these consumption patterns is vital for designing circuits that meet the desired energy requirements and performance specifications.

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Most popular questions from this chapter

You need to connect a 68 \(\mathrm{k} \Omega\) resistor and one other resistor to a 110 \(\mathrm{V}\) power line. If you want the two resistors to use 4 times as much power when connected in parallel as they use when connected in series, what should be the value of the unknown resistor?

Electric eels. Electric eels generate electric pulses along their skin that can be used to stun an enemy when they come into contact with it. Tests have shown that these pulses can be up to 500 \(\mathrm{V}\) and produce currents of 80 \(\mathrm{mA}\) (or even larger). A typical pulse lasts for 10 \(\mathrm{ms}\) . What power and how much energy are delivered to the unfortunate enemy with a single pulse, assuming a steady current?

A tightly coiled spring having 75 coils, each 3.50 \(\mathrm{cm}\) in diameter, is made of insulated metal wire 3.25 \(\mathrm{mm}\) in diameter. An ohmmeter connected across opposite ends of the spring reads 1.74\(\Omega .\) What is the resistivity of the metal?

A 6.00 \(\mu \mathrm{F}\) capacitor that is initially uncharged is connected in series with a 4500\(\Omega\) resistor and a 500 \(\mathrm{V}\) emf source with negligible internal resistance. Just after the circuit is completed, what are (a) the voltage drop across the capacitor, (b) the voltage drop across the resistor, (c) the charge on the capacitor, and (d) the current through the resistor? (e) A long time after the circuit is completed (after many time constants), what are the values of the preceding four quantities?

A 12.4 \(\mu \mathrm{F}\) capacitor is connected through a 0.895 \(\mathrm{M\Omega}\) resistor to a constant potential difference of 60.0 \(\mathrm{V}\) . (a) Compute the charge on the capacitor at the following times after the connections are made: \(0,5.0 \mathrm{s}, 10.0 \mathrm{s}, 20.0 \mathrm{s},\) and 100.0 \(\mathrm{s}\) . (b) Compute the charging currents at the same instants. (c) Graph the results of parts (a) and (b) for \(t\) between 0 and 20 \(\mathrm{s}\) .

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