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\(\bullet$$\bullet\) Initially at a temperature of \(80.0^{\circ} \mathrm{C}, 0.28 \mathrm{m}^{3}\) of air expands at a constant gauge pressure of \(1.38 \times 10^{5} \mathrm{Pa}\) to a volume of 1.42 \(\mathrm{m}^{3}\) and then expands further adiabatically to a final volume of 2.27 \(\mathrm{m}^{3}\) and a final gauge pressure of \(2.29 \times 10^{4} \mathrm{Pa}\). Draw a \(p V\) diagram for this sequence of processes, and compute the total work done by the air. \(C_{V}\) for air is 20.8 \(\mathrm{J} /(\mathrm{mol} \cdot \mathrm{K}) .\)

Short Answer

Expert verified
The total work done by the air is 157320 J.

Step by step solution

01

Isothermal Expansion Work

First, address the isothermal expansion from 0.28 m³ to 1.42 m³ at constant pressure. The work done by the air during this step can be calculated using:\[ W_1 = P(V_f - V_i) \]where \( P = 1.38 \times 10^5 \) Pa, \( V_i = 0.28 \) m³, and \( V_f = 1.42 \) m³. Calculate \( W_1 \):\[ W_1 = 1.38 \times 10^5 (1.42 - 0.28) = 1.38 \times 10^5 \times 1.14 = 157320 \ \text{J} \]
02

Adiabatic Expansion Parameters

In the second step, the system expands adiabatically. You need to use the adiabatic relationship:\[ P_1 V_1^\gamma = P_2 V_2^\gamma \]Here \( P_1 = 1.38 \times 10^5 \) Pa, \( V_1 = 1.42 \) m³, \( P_2 = 2.29 \times 10^4 \) Pa, and \( V_2 = 2.27 \) m³. First, determine \( \gamma \) using the relation \( \gamma = \frac{C_p}{C_v} \), where \( C_p - C_v = R \) and \( C_v = 20.8 \ \text{J/(mol} \cdot \text{K)} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Adiabatic Process
An adiabatic process is a transformation in which a gas changes its volume and pressure without gaining or losing heat. This means that all the work done on or by the gas comes from its internal energy. Such processes are rapid, so there's no time for heat exchange with the surroundings.
This process obeys the equation: \[ P_1 V_1^\gamma = P_2 V_2^\gamma \] where \( \gamma \) (gamma) is the adiabatic index or ratio of specific heats, typically \( \gamma = 1.4 \) for air when it behaves as an ideal diatomic gas.
In the context of the problem, the air expands adiabatically from a volume of 1.42 m³ to 2.27 m³. Understanding this helps to determine the profile of the trajectory in the Pressure-Volume diagram and calculate the work done during this phase without any heat entering or leaving the system.
Isothermal Process
An isothermal process occurs when a gas changes its volume and pressure while maintaining a constant temperature. For an ideal gas undergoing an isothermal process, the internal energy remains constant, and any work done by the gas is exactly balanced by heat entering or leaving the system.
Such processes often follow Boyle's Law, showing an inverse relationship between pressure and volume: \[ PV = ext{constant} \] During the first phase in the problem, the air expands from 0.28 m³ to 1.42 m³ under constant pressure, which can be understood as part of an isothermal process given the large temperature difference. The equation for work done here, \( W = P(V_f - V_i) \), stems from the need to consider how energy transfers in systems where temperature initially appears continuously stabilized.
Work Done by Gas
The work done by a gas during expansion or compression is linked to the energy transferred to or from the gas due to its volume change. In thermodynamic terms, work done by the gas is the product of pressure and the change in volume: \[ W = P \Delta V \] In scenarios involving an isothermal process, there is clear work done on the gas since the pressure remains constant. In adiabatic processes, the energy change is internal, so work results from converted internal energy.
In the exercise, the calculations are divided into two parts: work during isothermal expansion and work during adiabatic expansion. The final work done is the sum of these two quantities. Understanding this concept of work interaction is pivotal for calculating efficiency in engines or air conditioners where thermodyanamic cycles are modeled.
Pressure-Volume Diagram
A pressure-volume diagram (P-V diagram) represents changes in the pressure and volume of a gas system during thermodynamic processes. This visual tool is essential for observing the path taken during various stages of a process, especially in cycles like refrigeration or engines.
The x-axis commonly denotes volume, and the y-axis pressure, with plotted curves showing transitions like isothermal or adiabatic paths.
In the given problem, you'd depict two sections: - A horizontal line corresponding to the isothermal expansion since pressure is constant. - A curved line dropping to the right, illustrating adiabatic expansion showing a decrease in both pressure and mechanically useful work output while no heat is transferred. Reading and interpreting these diagrams assists learners in visualizing abstract thermodynamic principles, promoting a deeper understanding of real-world applications.

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Most popular questions from this chapter

\(\bullet\) Three moles of an ideal gas are in a rigid cubical box with sides of length 0.200 \(\mathrm{m} .\) (a) What is the force that the gas exerts on each of the six sides of the box when the gas temperature is \(20.0^{\circ} \mathrm{C}\) ? (b) What is the force when the temperature of the gas is increased to \(100.0^{\circ} \mathrm{C} ?\)

\(\bullet\) \(\bullet\) A diver observes a bubble of air rising from the bottom of a lake (where the absolute pressure is 3.50 atm ) to the surface (where the pressure is 1.00 atm). The temperature at the bottom is \(4.0^{\circ} \mathrm{C}\) and the temperature at the surface is \(23.0^{\circ} \mathrm{C}\) . $$\begin{array}{l}{\text { (a) What is the ratio of the volume of the bubble as it reaches }} \\ {\text { the surface to its volume at the bottom? (b) Would it be safe }} \\ {\text { for the diver to hold his breath while ascending from the bottom of the lake to the surface? Why or why not? }}\end{array}$$

\(\bullet$$\bullet\) (a) A deuteron, \(_{1}^{2} \mathrm{H},\) is the nucleus of a hydrogen isotope and consists of one proton and one neutron. The plasma of deuterons in a nuclear fusion reactor must be heated to about 300 million K. What is the rms speed of the deuterons? Is this a significant fraction of the speed of light \(\left(c=3.0 \times 10^{8} \mathrm{m} / \mathrm{s}\right) ?(\mathrm{b})\) What would the temperature of the plasma be if the deuterons had an rms speed equal to 0.10\(c ?\)

\(\bullet\) Modern vacuum pumps make it easy to attain pressures on the order of \(10^{-13}\) atm in the laboratory. At a pressure of \(9.00 \times 10^{-14}\) atm and an ordinary temperature of \(300 \mathrm{K},\) how many molecules are present in 1.00 \(\mathrm{cm}^{3}\) of gas?

\(\bullet$$\bullet\) The bends. If deep-sea divers rise to the surface too quickly, nitrogen bubbles in their blood can expand and prove fatal. This phenomenon is known as the bends. If a scuba diver rises quickly from a depth of 25 \(\mathrm{m}\) in Lake Michigan (which is free water), what will be the volume at the surface of an \(\mathrm{N}_{2}\) bubble that occupied 1.0 \(\mathrm{mm}^{3}\) in his blood at the lower depth? Does it seem that this difference is large enough to be a problem? (Assume that the pressure difference is due only to the changing water pressure, not to any temperature difference, an assumption that is reasonable, since we are warm-blooded creatures.)

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