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\(\bullet\) Modern vacuum pumps make it easy to attain pressures on the order of \(10^{-13}\) atm in the laboratory. At a pressure of \(9.00 \times 10^{-14}\) atm and an ordinary temperature of \(300 \mathrm{K},\) how many molecules are present in 1.00 \(\mathrm{cm}^{3}\) of gas?

Short Answer

Expert verified
There are approximately \(2.44 \times 10^6\) molecules in 1.00 cm³ of gas.

Step by step solution

01

Identify the Ideal Gas Law

To solve this problem, we'll use the ideal gas law, which is expressed as \( PV = nRT \), where \( P \) is pressure, \( V \) is volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is temperature.
02

Convert Units

Ensure all units are in standard SI units. The pressure is given in atm, so we convert it to Pa using \( 1 \, \text{atm} = 1.01325 \times 10^5 \, \text{Pa} \). Thus, \( 9.00 \times 10^{-14} \, \text{atm} = 9.00 \times 10^{-14} \times 1.01325 \times 10^5 \, \text{Pa} \). Volume \( V = 1.00 \, \text{cm}^3 = 1.00 \times 10^{-6} \, \text{m}^3 \), and temperature remains \( T = 300 \, \text{K} \).
03

Plug Values into Ideal Gas Law

Rearrange the ideal gas law to \( n = \frac{PV}{RT} \) and plug in the converted values: \[ P = 9.00 \times 10^{-14} \times 1.01325 \times 10^5 \, \text{Pa}, V = 1.00 \times 10^{-6} \, \text{m}^3, R = 8.314 \, \text{JK}^{-1}\text{mol}^{-1}, T = 300 \, \text{K} \].
04

Calculate Number of Moles

Perform the calculation to find the number of moles per cubic meter: \( n = \frac{9.00 \times 10^{-14} \times 1.01325 \times 10^5 \times 1.00 \times 10^{-6}}{8.314 \times 300} \).
05

Convert Moles to Molecules

The number of molecules is found by multiplying the number of moles by Avogadro's number, \( 6.022 \times 10^{23} \). Calculate \( N = n \times 6.022 \times 10^{23} \) to find the number of molecules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vacuum Pumps
Vacuum pumps are essential tools used in laboratories to create low-pressure environments by removing air and other gases from a sealed space. In scientific investigations and experiments, it allows researchers to attain pressures as low as \(10^{-13}\) atm. This level of vacuum is beneficial for various purposes, including studying gas behavior under extremely reduced pressures.
By understanding ideal gas behavior in partial vacuums, we can see the impact such low pressures have on the properties of gases. Maintaining a vacuum involves two key processes:
  • Evacuation: Removing gases from a volume using a pump system.
  • Regulation: Stabilizing and controlling the pressure in the vacuum environment.
With proper vacuum management, we gain insights into molecular interactions and the efficacy of vacuum systems in both experimental and industrial settings.
Avogadro's Number
Avogadro's number is a fundamental constant in chemistry that defines the number of particles, typically atoms or molecules, in one mole of a substance. This large number is valued at \(6.022 \times 10^{23}\) particles per mole.
Avogadro's number provides a bridge between the macroscopic scale of substances we can measure and the microscopic scale of particles:
  • By knowing the number of molecules present with Avogadro's number, we can transition between moles, which are convenient for laboratory use, and molecule count for precise scientific calculations.
  • It aids in quantifying quantities of substances without dealing directly in molecular scales, which is impractical in bulk measurements.
In solving gas-related problems, multiplying the number of moles by Avogadro's number gives the total number of molecules, a necessary step in determining the total molecular quantity in specific volumes.
SI Units
The International System of Units (SI) is the standard metric system used globally in scientific and everyday measurements. In the ideal gas law and related calculations, adhering to SI units ensures consistency and comparability of results.
Key SI units commonly used in gas law calculations include:
  • Pressure, measured in Pascals (Pa) after converting from other units like atmospheres (atm):\(1 \, \text{atm} = 1.01325 \times 10^{5} \, \text{Pa}\).
  • Volume, measured in cubic meters (m^3), which requires converting from other common units like cubic centimeters (cm^3).
  • Temperature, measured in Kelvin (K), the standard unit for thermodynamic temperature in scientific calculations.
Using SI units aids in avoiding conversion errors and simplifying calculations, providing a universally accepted system for scientific discourse and education.
Pressure Conversion
Pressure conversion is crucial when working with various units, especially since pressure is commonly measured in different units like atmospheres (atm) or Pascals (Pa).
Having a clear understanding of conversions allows accurate application of the ideal gas law, which is sensitive to unit consistency:
  • To convert from atm to Pa, use \(1 \, \text{atm} = 1.01325 \times 10^{5} \, \text{Pa}\), ensuring all calculations in the ideal gas law are performed using SI units.
  • Understanding pressure conversion offers broader insights into practical applications, such as understanding weather patterns, hydraulic systems, and conditions in different scientific experiments.
Accurate handling of units allows students and scientists to seamlessly interpret data and apply findings across various disciplines, emphasizing the importance of unit conversion in scientific studies.

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Most popular questions from this chapter

\(\bullet\) A gas in a cylinder expands from a volume of 0.110 \(\mathrm{m}^{3}\) to 0.320 \(\mathrm{m}^{3} .\) Heat flows into the gas just rapidly enough to keep the pressure constant at \(1.80 \times 10^{5} \mathrm{Pa}\) during the expansion. The total heat added is \(1.15 \times 10^{5} \mathrm{J}\) . (a) Find the work done by the gas. (b) Find the change in internal energy of the gas.

\(\bullet$$\bullet\) A bicyclist uses a tire pump whose cylinder is initially full of air at an absolute pressure of \(1.01 \times 10^{5}\) Pa. The length of stroke of the pump (the length of the cylinder) is 36.0 \(\mathrm{cm}\) . At what part of the stroke (i.e., what length of the air column) does air begin to enter a tire in which the gauge pressure is \(2.76 \times 10^{5} \mathrm{Pa} ?\) Assume that the temperature remains constant during the compression.

\(\bullet\) The gas inside a balloon will always have a pressure nearly equal to atmospheric pressure, since that is the pressure applied to the outside of the balloon. You fill a balloon with helium (a nearly ideal gas) to a volume of 0.600 L at a temperature of \(19.0^{\circ} \mathrm{C}\) . What is the volume of the balloon if you cool it to the boiling point of liquid nitrogen \((77.3 \mathrm{K})\) ?

\(\bullet$$\bullet\) The surface of the sun. The surface of the sun has a temperature of about 5800 \(\mathrm{K}\) and consists largely of hydrogen atoms. (a) Find the rms speed of a hydrogen atom at this temperature. (The mass of a single hydrogen atom is \(1.67 \times\) \(10^{-27} \mathrm{kg} .\) (b) What would be the mass of an atom that had half the rms speed of hydrogen?

\(\bullet\) A cylinder contains 0.250 mol of carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) gas at a temperature of \(27.0^{\circ} \mathrm{C}\) . The cylinder is provided with a frictionless piston, which maintains a constant pressure of 1.00 atm on the gas. The gas is heated until its temperature increases to \(127.0^{\circ} \mathrm{C}\) . Assume that the \(\mathrm{CO}_{2}\) may be treated as an ideal gas. (a) Draw a \(p V\) diagram of this process. (b) How much work is done by the gas in the process? (c) On what is this work done? (d) What is the change in internal energy of the gas? (e) How much heat was supplied to the gas? (f) How much work would have been done if the pressure had been 0.50 atm?

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