/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 (a) Calculate the buoyant force ... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) Calculate the buoyant force of air (density 1.20 \(\mathrm{kg} / \mathrm{m}^{3} )\) on a spherical party balloon that has a radius of 15.0 \(\mathrm{cm}\) . (b) If the rubber of the balloon itself has a mass of 2.00 \(\mathrm{g}\) and the balloon is filled with helium (density 0.166 \(\mathrm{kg} / \mathrm{m}^{3}\) ), calculate the net upward force (the "lift") that acts on it in air.

Short Answer

Expert verified
(a) The buoyant force is 0.166 N. (b) The net upward force is approximately 0.1234 N.

Step by step solution

01

Convert Radius to Meters

The radius of the balloon is given as 15.0 cm. First, convert this to meters by dividing by 100: \[ 15.0 \text{ cm} = 0.15 \text{ m} \]
02

Calculate Volume of the Balloon

With the radius converted to meters, calculate the volume of the balloon using the formula for the volume of a sphere: \[ V = \frac{4}{3} \pi r^3 \] Substituting the radius, \[ V = \frac{4}{3} \pi (0.15)^3 \approx 0.0141 \text{ m}^3 \]
03

Calculate Buoyant Force

The buoyant force can be calculated using the formula: \[ F_{b} = \rho_{\text{air}} \cdot V \cdot g \] where \( \rho_{\text{air}} = 1.20 \text{ kg/m}^3 \), \( V = 0.0141 \text{ m}^3 \) and \( g = 9.81 \text{ m/s}^2 \). Substituting the values,\[ F_{b} = 1.20 \times 0.0141 \times 9.81 \approx 0.166 \text{ N} \]
04

Calculate Mass of Helium

Determine the mass of helium in the balloon using the formula: \[ m = \rho_{\text{He}} \cdot V \] where \( \rho_{\text{He}} = 0.166 \text{ kg/m}^3 \). So,\[ m = 0.166 \times 0.0141 \approx 0.00234 \text{ kg} \]
05

Total Mass of Balloon

Add the mass of the rubber to the mass of the helium to find the total mass:\[ m_{\text{total}} = m_{\text{He}} + m_{\text{rubber}} \]Converting the mass of the rubber from grams to kilograms: \[ m_{\text{rubber}} = 2.00 \text{ g} = 0.00200 \text{ kg} \]Thus,\[ m_{\text{total}} = 0.00234 + 0.00200 = 0.00434 \text{ kg} \]
06

Calculate Weight of the Balloon

The weight of the balloon is found using:\[ W = m_{\text{total}} \cdot g \]Substituting the total mass and gravitational acceleration,\[ W = 0.00434 \times 9.81 \approx 0.0426 \text{ N} \]
07

Calculate Net Upward Force

Net force ("lift") is the difference between the buoyant force and the weight of the balloon. \[ \text{Net force} = F_{b} - W \]Substitute the values:\[ \text{Net force} = 0.166 - 0.0426 \approx 0.1234 \text{ N} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a measure of how much mass is packed into a given volume. It's a crucial concept in understanding buoyant forces and the behavior of different substances in fluids. Mathematically, density (\( \rho \)) is expressed as mass divided by volume, or \( \rho = \frac{m}{V} \).
For example, in our balloon problem, the densities of air and helium are given as 1.20 kg/m³ and 0.166 kg/m³, respectively. This means that air is denser than helium. This difference in density is key to the balloon's ability to float when filled with helium.
  • Each substance has its own characteristic density.
  • Floating or sinking depends on comparing the density of the object to the fluid surrounding it.
  • Lower density substances float on higher density fluids.
A helium-filled balloon rises because helium's density is less than that of the surrounding air. Understanding density helps us predict and calculate how different substances will behave when immersed in a fluid.
Net Upward Force
The net upward force, often referred to as "lift," is the force that determines whether an object will rise, float, or sink in a fluid. It's the difference between the buoyant force exerted by the fluid and the object's weight.
In our balloon scenario, the net upward force is calculated as follows:
  • The buoyant force is the force with which the air pushes the balloon upwards.
  • The weight of the balloon includes both the mass of the helium inside and the balloon's material.
  • Subtract the weight from the buoyant force to get the net upward force.
In formula form, this can be seen as: \[ \text{Net force} = F_{b} - W \] Where \( F_{b} \) is the buoyant force and \( W \) is weight. If the net force is positive, the balloon will rise; if negative, it will sink; if zero, it will float suspended. In our example, the net upward force came out to approximately 0.1234 N, allowing the balloon to rise in the air.
Volume of a Sphere
The volume of an object tells us how much space it occupies. For spherical objects like balloons, calculating the volume involves a specific formula due to their round 3D shape: \[ V = \frac{4}{3} \pi r^3 \] where \( r \) is the radius of the sphere.
In our problem, the radius of the balloon is 0.15 meters. Plugging this radius into the formula, we found the volume to be approximately 0.0141 m³.
  • The volume helps determine how much fluid is displaced when the sphere is submerged, crucial for calculating buoyant forces.
  • Larger volumes displace more fluid, leading to larger buoyant forces.
The volume is a fundamental part of finding the buoyant force using Archimedes' principle, which states that the buoyant force is equal to the weight of the displaced fluid. This is why knowing the volume is essential in buoyancy calculations for balloons.

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Most popular questions from this chapter

A cube of compressible material (such as Styrofoam or balsa wood) has a density \(\rho\) and sides of length \(L .\) (a) If you keep its mass the same, but compress each side to half its length, what will be its new density, in terms of \(\rho ?\) (b) If you keep the mass and shape the same, what would the length of each side have to be (in terms of \(L )\) so that the density of the cube was three times its original value?

By how many newtons do you increase the weight of your car when you fill up your 11.5 gal gas tank with gasoline? A gallon is equal to 3.788 \(\mathrm{L}\) and the density of gasoline is 737 \(\mathrm{kg} / \mathrm{m}^{3}\) .

Blood. (a) Mass of blood. The human body typically contains 5 L of blood of density 1060 \(\mathrm{kg} / \mathrm{m}^{3} .\) How many kilograms of blood are in the body? (b) The average blood pressure is \(13,000 \mathrm{Pa}\) at the heart. What average force does the blood exert on each square centimeter of the heart? (c) Red blood cells. Red blood cells have a specific gravity of 5.0 and a diameter of about 7.5\(\mu \mathrm{m}\) . If they are spherical in shape (which is not quite true), what is the mass of such a cell?

Blood pressure. Systemic blood pressure is defined as the ratio of two pressures, both expressed in millimeters of mercury. Normal blood pressure is about \(\frac{120 \mathrm{mm}}{80 \mathrm{mm}},\) which is usually just stated as \(\frac{120}{80}\) . (See also Problem \(24 . )\) What would normal systemic blood pressure be if, instead of millimeters of mercury, we expressed pressure in each of the following units, but continued to use the same ratio format? (a) atmospheres, (b) torr, (c) Pa, (d) \(\mathrm{N} / \mathrm{m}^{2},\) (e) psi.

Landing on Venus. One of the great difficulties in landing on Venus is dealing with the crushing pressure of the atmosphere, which is 92 times the earth's atmospheric pressure. (a) If you are designing a lander for Venus in the shape of a hemisphere 2.5 \(\mathrm{m}\) in diameter, how many newtons of inward force must it be prepared to withstand due to the Venusian atmosphere? (Don't forget about the bottom!) (b) How much force would the lander have to withstand on the earth?

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