/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Glaucoma. Under normal circumsta... [FREE SOLUTION] | 91Ó°ÊÓ

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Glaucoma. Under normal circumstances, the vitreous humor, a jelly-like substance in the main part of the eye, exerts a pressure of up to 24 \(\mathrm{mm}\) of mercury that maintains the shape of the eye. If blockage of the drainage duct for aqueous humor causes this pressure to increase to about 50 \(\mathrm{mm}\) of mercury, the condition is called glaucoma. What is the increase in the total force (in newtons) on the walls of the eye if the pressure increases from 24 \(\mathrm{mm}\) to 50 \(\mathrm{mm}\) of mercury? We can quite accurately model the eye as a sphere 2.5 \(\mathrm{cm}\) in diameter.

Short Answer

Expert verified
The increase in total force is approximately 6.805 N.

Step by step solution

01

Calculate the Pressure Increase

First, determine the change in pressure by subtracting the normal pressure from the elevated pressure experienced due to glaucoma. The initial normal pressure is given as 24 mm of mercury, and the increased pressure is 50 mm of mercury.\[\Delta P = P_{final} - P_{initial} = 50 \ \mathrm{mmHg} - 24 \ \mathrm{mmHg} = 26 \ \mathrm{mmHg}\]
02

Convert Pressure Change to Pascals

To calculate the force increase in newtons, we need to convert the pressure from mm of mercury to pascals (since 1 mmHg = 133.322 Pa).\[\Delta P (\text{in Pa}) = 26 \ \mathrm{mmHg} \times 133.322 \ \mathrm{Pa/mmHg} = 3466.372 \ \mathrm{Pa}\]
03

Calculate the Surface Area of the Eye

Assume the eye is a sphere with a diameter of 2.5 cm. First, convert the diameter to meters (0.025 m) and then calculate the surface area. The formula for the surface area of a sphere is:\[A = 4\pi r^2\]Where \( r \) is the radius of the sphere. The radius is half of the diameter:\[ r = \frac{2.5 \ \mathrm{cm}}{2} = 1.25 \ \mathrm{cm} = 0.0125 \ \mathrm{m} \]Calculate the surface area:\[A = 4\pi (0.0125 \ \mathrm{m})^2 = 1.9635 \times 10^{-3} \ \mathrm{m}^2\]
04

Calculate the Increase in Force on the Eye's Surface

The increase in force is found by multiplying the change in pressure by the surface area of the sphere (the eye).\[\Delta F = \Delta P \times A = 3466.372 \ \mathrm{Pa} \times 1.9635 \times 10^{-3} \ \mathrm{m}^2\]\[\Delta F = 6.805 \ \mathrm{N}\]
05

Interpret the Result

The solution shows that the increase in total force due to the pressure change is approximately 6.805 newtons. This increase reflects how much additional force is applied to the eye's surface when the pressure rises from 24 mmHg to 50 mmHg, due to the onset of glaucoma.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pressure Conversion
Understanding the concept of pressure conversion is crucial when working with units like millimeters of mercury (mmHg) and pascals (Pa). These units measure pressure, which is defined as the force exerted per unit area. In this problem, you are dealing with pressure exerted by the fluids in the eye, commonly measured in mmHg due to its medical relevance. However, to find the force in newtons, you must convert this pressure into pascals, the SI unit for pressure.

To convert pressure from mmHg to pascals, use the conversion factor: 1 mmHg equals 133.322 Pa. Using this relation, if you have a pressure difference from 24 mmHg to 50 mmHg, the difference is 26 mmHg. Multiply this difference by 133.322 to convert it to pascals:
  • Calculation: \(26 \ \mathrm{mmHg} \times 133.322 \ \mathrm{Pa/mmHg} = 3466.372 \ \mathrm{Pa}\)
Understanding this conversion is key because drag and force calculations usually require inputs in SI units for consistency and precision. It helps us quantify exactly how much pressure—and thus force—could affect structures like the eye in medical contexts like glaucoma.
Force Calculation
Once you've converted the pressure change into pascals, calculating the force acting on the eye's surface is straightforward with the formula:\[\Delta F = \Delta P \times A\]Where \(\Delta F\) is the change in force, \(\Delta P\) is the change in pressure in pascals, and \(A\) is the surface area of the sphere, which models the eye.

In this exercise, after converting the pressure change of 26 mmHg to 3466.372 Pa, you multiply this by the surface area of the eye to get the force. First, understand that force units of newtons are derived from multiplying pascals and square meters. The calculation captures how an increase in pressure directly translates to an increased force over a given area.

Increasing the pressure from 24 mmHg to 50 mmHg results in an additional force of about 6.805 N on the eye's surface. This concept is vital in fields such as ophthalmology, where understanding force changes can predict physical effects within the eye, as seen with glaucoma.
Surface Area of a Sphere
To model the eye's surface area, we use the geometry of a sphere. The eye, though not a perfect sphere, is similar enough that this model works for problems regarding internal pressure. The formula for the surface area \(A\) of a sphere is:\[A = 4\pi r^2\]where \(r\) is the radius. In this situation, the diameter of the eye is given as 2.5 cm. Remember to convert this measurement into meters because the SI unit for distance is the meter.

The radius is half of the diameter, so:
  • Diameter = 2.5 cm
  • Radius = 1.25 cm = 0.0125 m
Now, plugging this radius into the formula gives you the required surface area:
  • Calculation: \(4\pi (0.0125 \ \mathrm{m})^2 = 1.9635 \times 10^{-3} \ \mathrm{m}^2\)
This surface area is essential for calculating the force due to pressure changes, helping quantify how mechanical forces act on the eye. By applying this calculation, we understand how the eye's shape and size affect the physical pressures it can withstand.

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Most popular questions from this chapter

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