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For the following objects, which all roll without slipping, determine the rotational kinetic energy about the center of mass as a percentage of the total kinetic energy: (a) a solid sphere, (b) a thin spherical shell, and (c) a thin cylindrical shell.

Short Answer

Expert verified
For a solid sphere: 28.57%, thin spherical shell: 40%, thin cylindrical shell: 50%.

Step by step solution

01

Understand the Concept of Rotational Kinetic Energy and Total Kinetic Energy

The rotational kinetic energy of an object is the energy due to its rotation and is given by the formula \( KE_{rot} = \frac{1}{2} I \omega^2 \), where \( I \) is the moment of inertia, and \( \omega \) is the angular velocity. For an object that rolls without slipping, the total kinetic energy \( KE_{total} \) is the sum of the translational kinetic energy and the rotational kinetic energy.
02

Find the Moment of Inertia for Each Object

The moment of inertia \( I \) differs for each object.- **Solid sphere:** \( I = \frac{2}{5} m r^2 \)- **Thin spherical shell:** \( I = \frac{2}{3} m r^2 \)- **Thin cylindrical shell:** \( I = m r^2 \)Here, \( m \) is the mass of the object, and \( r \) is the radius.
03

Relate Angular Velocity and Linear Velocity

For rolling without slipping, the relationship between linear velocity \( v \) and angular velocity \( \omega \) is \( v = r \omega \). Thus, \( \omega = \frac{v}{r} \).
04

Calculate Rotational Kinetic Energy in Terms of Linear Velocity

Substitute \( \omega = \frac{v}{r} \) into the rotational kinetic energy formula:- **Solid sphere:** \( KE_{rot} = \frac{1}{2} \times \frac{2}{5} m r^2 \times \left(\frac{v}{r}\right)^2 = \frac{1}{5} m v^2 \)- **Thin spherical shell:** \( KE_{rot} = \frac{1}{2} \times \frac{2}{3} m r^2 \times \left(\frac{v}{r}\right)^2 = \frac{1}{3} m v^2 \)- **Thin cylindrical shell:** \( KE_{rot} = \frac{1}{2} \times m r^2 \times \left(\frac{v}{r}\right)^2 = \frac{1}{2} m v^2 \)
05

Calculate Total Kinetic Energy for Each Object

The total kinetic energy includes both translational and rotational components:- **Translational kinetic energy:** \( KE_{trans} = \frac{1}{2} m v^2 \)So for each object, the total kinetic energy is:- **Solid sphere:** \( KE_{total} = \frac{1}{2} m v^2 + \frac{1}{5} m v^2 = \frac{7}{10} m v^2 \)- **Thin spherical shell:** \( KE_{total} = \frac{1}{2} m v^2 + \frac{1}{3} m v^2 = \frac{5}{6} m v^2 \)- **Thin cylindrical shell:** \( KE_{total} = \frac{1}{2} m v^2 + \frac{1}{2} m v^2 = m v^2 \)
06

Determine Rotational Kinetic Energy as a Percentage of Total Kinetic Energy

Calculate the percentage for each object:- **Solid sphere:** \( \frac{\frac{1}{5} m v^2}{\frac{7}{10} m v^2} \times 100\% = 28.57\% \)- **Thin spherical shell:** \( \frac{1}{3} m v^2}{\frac{5}{6} m v^2} \times 100\% = 40\% \)- **Thin cylindrical shell:** \( \frac{1}{2} m v^2}{m v^2} \times 100\% = 50\% \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
The moment of inertia, often represented by the symbol \( I \), is a key concept when analyzing rotational motion. It serves as a measure of an object's resistance to changes in its rotational motion, much like mass is a measure of resistance to changes in translational motion. It depends on two main factors: the mass of the object and how that mass is distributed relative to the axis of rotation. This is why different shapes and mass distributions lead to different moments of inertia. For example, a solid sphere has a moment of inertia of \( I = \frac{2}{5} m r^2 \), while a thin spherical shell has \( I = \frac{2}{3} m r^2 \), and a thin cylindrical shell has \( I = m r^2 \). Each formula accounts for how the mass is spread out relative to the rotation axis. Understanding the moment of inertia helps in predicting how an object will behave when it is subject to rotational forces.
Rolling Without Slipping
"Rolling without slipping" is a common phrase in physics that describes a situation where an object rolls along a surface, and there is no relative motion between the point of contact on the object and the surface. This implies that the object is perfectly rolling instead of skidding or sliding, which means that the linear velocity of the object's center of mass is precisely matched to its rotational motion. This concept can be mathematically expressed as \( v = r \omega \), where \( v \) is the linear velocity of the center of mass, \( r \) is the radius of the object, and \( \omega \) is its angular velocity. This relationship ensures that rotational and translational motions are properly synchronized and allows for seamless conversion between the two, often used in the calculation of total kinetic energy in rolling objects.
Translational Kinetic Energy
Translational kinetic energy is the kinetic energy associated with the movement of an object's center of mass as it transitions from one location to another. It differs from rotational kinetic energy, which accounts for the object's rotation about its axis. Translational kinetic energy is given by the formula \( KE_{trans} = \frac{1}{2} m v^2 \), where \( m \) is the mass of the object and \( v \) is its linear velocity. When an object rolls without slipping, both translational and rotational kinetic energies must be considered to find the total kinetic energy \( KE_{total} \). For instance, when evaluating objects like a solid sphere or a thin shell, calculating their total energy requires adding both types of kinetic energies, as they contribute unique aspects of the object's motion. Understanding this concept is crucial in solving problems related to rolling motion and energy distribution in rotational systems.

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Most popular questions from this chapter

A planetary space probe is in the shape of a cylinder. To protect it from heat on one side (from the Sun's rays), operators on the Earth put it into a "barbecue mode," that is, they set it rotating about its long axis. To do this, they fire four small rockets mounted tangentially as shown in \(v\) Fig. 8.51 (the probe is shown coming toward you). The object is to get the probe to rotate completely once every \(30 \mathrm{~s}\), starting from no rotation at all. They wish to do this by firing all four rockets for a certain length of time. Each rocket can exert a thrust of \(50.0 \mathrm{~N}\). Assume the probe is a uniform solid cylinder with a radius of \(2.50 \mathrm{~m}\) and a mass of \(1000 \mathrm{~kg}\) and neglect the mass of each rocket engine. Determine the amount of time the rockets need to be fired.

A fixed 0.15-kg solid-disk pulley with a radius of \(0.075 \mathrm{~m}\) is acted on by a net torque of \(6.4 \mathrm{~m} \cdot \mathrm{N}\). What is the angular acceleration of the pulley?

A bocce ball with a diameter of \(6.00 \mathrm{~cm}\) rolls without slipping on a level lawn. It has an initial angular speed of \(2.35 \mathrm{rad} / \mathrm{s}\) and comes to rest after \(2.50 \mathrm{~m}\). Assuming constant deceleration, determine (a) the magnitude of its angular deceleration and (b) the magnitude of the maximum tangential acceleration of the ball's surface (tell where that part is located)

Circular disks are used in automobile clutches and transmissions. When a rotating disk couples to a stationary one through frictional force, the energy from the rotating disk can transfer to the stationary one. (a) Is the angular speed of the coupled disks (1) greater than, (2) less than, or (3) the same as the angular speed of the original rotating disk? Why? (b) If a disk rotating at 800 rpm couples to a stationary disk with three times the moment of inertia, what is the angular speed of the combination?

A 10 -kg rotating disk of radius \(0.25 \mathrm{~m}\) has an angular momentum of \(0.45 \mathrm{~kg} \cdot \mathrm{m}^{2} / \mathrm{s}\) What is the angular speed of the disk?

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