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A fixed 0.15-kg solid-disk pulley with a radius of \(0.075 \mathrm{~m}\) is acted on by a net torque of \(6.4 \mathrm{~m} \cdot \mathrm{N}\). What is the angular acceleration of the pulley?

Short Answer

Expert verified
The angular acceleration of the pulley is approximately \(15172.1\,\text{rad/s}^2\).

Step by step solution

01

Identify Known Variables

We have a solid-disk pulley with a mass of \(0.15\,\text{kg}\) and a radius of \(0.075\,\text{m}\). The net torque applied on it is \(6.4\,\text{N} \cdot \text{m}\).
02

Recall the Formula for Moment of Inertia

For a solid disk, the moment of inertia \(I\) is given by \(I = \frac{1}{2} m r^2\), where \(m\) is the mass and \(r\) is the radius of the disk.
03

Calculate the Moment of Inertia

Substitute the given values into the formula: \[ I = \frac{1}{2} \times 0.15\,\text{kg} \times (0.075\,\text{m})^2 \].Calculate this to find \(I = 0.000421875\,\text{kg} \cdot \text{m}^2\).
04

Use the Relationship between Torque and Angular Acceleration

The net torque \(\tau\) on an object is related to its moment of inertia \(I\) and its angular acceleration \(\alpha\) by the equation \(\tau = I \alpha\).
05

Solve for Angular Acceleration

Rearrange the equation to solve for \(\alpha\): \(\alpha = \frac{\tau}{I}\).Substitute the known values: \(\alpha = \frac{6.4}{0.000421875}\).Calculate \(\alpha \approx 15172.1\,\text{rad/s}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Moment of Inertia
Moment of inertia is a core concept in rotational dynamics, and it plays a role similar to mass in linear motion. It quantifies how much torque is required for a desired angular acceleration about a rotation axis. In simple terms, it measures an object's resistance to change in its rotational motion. For different shaped objects, the moment of inertia is calculated using different formulas.

For a **solid disk** like in the provided exercise, the moment of inertia **I** is given by the formula:
  • \[ I = \frac{1}{2} m r^2 \]
This tells us that the moment of inertia depends on both the mass \(m\) and the square of the radius \(r\) of the object. Thus, larger or more massive objects have a greater moment of inertia, requiring more torque to achieve the same angular acceleration.
The calculated moment of inertia for the solid-disk pulley is **0.000421875 kg·m²**. Understanding this concept is vital, as it will directly influence how an object responds to applied torques.
Exploring Torque
Torque is essentially a force that causes an object to rotate about an axis. Just like a force can make an object accelerate, torque can make an object spin faster or slower. Torque is defined as the product of the force applied and the distance from the point of rotation to where the force is acting, also known as the lever arm.

Mathematically, torque \( \tau \) is expressed as:
  • \[ \tau = r \times F \]
where \(r\) is the radius or lever arm, and \(F\) is the perpendicular force applied.

In our exercise, a net torque of **6.4 N·m** is applied to the pulley. The importance of finding torque lies in its direct relationship with angular acceleration via the moment of inertia. The greater the torque applied (for the same moment of inertia), the greater the angular acceleration achieved.
Solid-Disk Pulley
A solid-disk pulley is a commonly used rotating mechanism characterized by having its mass distributed evenly throughout the disk. This makes its calculations relatively straightforward when dealing with moment of inertia.

One of the defining features of the solid-disk pulley is how uniform mass distribution simplifies its rotational properties:
  • Its moment of inertia \(I\) is thus calculated with a consistent formula that applies to any size of solid disk, as shown previously.
  • This even mass spread contributes to a predictable response to applied torque, making it an essential component in systems involving belts, ropes, or cables.
In the context of the exercise, understanding the properties of the solid-disk pulley allows one to predict that as torque is applied, the disk will experience a uniform angular acceleration according to the physics principles of rotational motion.
Thus, for practical applications, such pulleys are integral in engineering, allowing precise control of mechanical systems where rotation and handling of tension are required.

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Most popular questions from this chapter

For the following objects, which all roll without slipping, determine the rotational kinetic energy about the center of mass as a percentage of the total kinetic energy: (a) a solid sphere, (b) a thin spherical shell, and (c) a thin cylindrical shell.

A uniform meterstick pivoted at its center, as in Example 8.5 , has a 100 -g mass suspended at the 25.0 -cm position. (a) At what position should a 75.0 - \(\mathrm{g}\) mass be suspended to put the system in equilibrium? (b) What mass would have to be suspended at the \(90.0-\mathrm{cm}\) position for the system to be in equilibrium?

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