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Find the magnitude of the linear momentum of (a) a \(7.1-\mathrm{kg}\) bowling ball traveling at \(12 \mathrm{~m} / \mathrm{s}\) and \((\mathrm{b})\) a \(1200-\mathrm{kg}\) automobile traveling at \(90 \mathrm{~km} / \mathrm{h}\).

Short Answer

Expert verified
Bowling Ball: 85.2 kg·m/s; Automobile: 30000 kg·m/s.

Step by step solution

01

Understanding Linear Momentum

Linear momentum is the product of an object's mass and velocity. It is given by the formula: \( p = mv \), where \( p \) is the linear momentum, \( m \) is the mass, and \( v \) is the velocity.
02

Convert Units for the Automobile

Before calculating the momentum for the automobile, convert its velocity from kilometers per hour to meters per second. Using the conversion: \(1 \, \text{km/h} = \frac{1}{3.6} \, \text{m/s}\), we get: \[ v = 90 \, \text{km/h} = 90 \times \frac{1}{3.6} \, \text{m/s} \approx 25 \, \text{m/s} \]
03

Calculate Momentum for the Bowling Ball

Use the momentum formula for the bowling ball: \( m = 7.1 \, \text{kg} \), \( v = 12 \, \text{m/s} \) Calculate: \[ p = mv = 7.1 \, \text{kg} \times 12 \, \text{m/s} = 85.2 \, \text{kg} \cdot \text{m/s} \]
04

Calculate Momentum for the Automobile

Use the momentum formula for the automobile with the converted velocity: \( m = 1200 \, \text{kg} \), \( v = 25 \, \text{m/s} \) (after conversion) Calculate: \[ p = mv = 1200 \, \text{kg} \times 25 \, \text{m/s} = 30000 \, \text{kg} \cdot \text{m/s} \]
05

Conclude With Results

The linear momentum of the bowling ball is \(85.2 \, \text{kg} \cdot \text{m/s}\), and the linear momentum of the automobile is \(30000 \, \text{kg} \cdot \text{m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass and Velocity
To understand linear momentum, we first need to understand its components: mass and velocity. Mass refers to how much matter an object contains, often measured in kilograms. It determines how much an object resists acceleration when a force is applied. Velocity, on the other hand, refers to the speed of the object in a specific direction, typically measured in meters per second (m/s). Velocity is not just about how fast something moves; it's also about the direction it's moving in. Together, these two factors form the core of linear momentum.
  • Mass - A scalar quantity indicating the amount of matter.
  • Velocity - A vector quantity indicating speed and direction.
Imagine a heavy object like a bowling ball or a light object like a feather. Both have mass, but the bowling ball’s larger mass means it carries more momentum at the same speed. Similarly, if two identical cars travel at different speeds, the faster car has more momentum because of its higher velocity.
Unit Conversion
Before calculating linear momentum, it's essential to have consistent measurement units. Often, we need to convert units to ensure they align properly for accurate calculations. This is known as unit conversion. For instance, you might have measured velocity in kilometers per hour (km/h) but need to convert this to meters per second (m/s) for consistency with the International System of Units (SI).
The conversion factor from kilometers per hour to meters per second is:
  • To convert, multiply the velocity by \( \frac{1}{3.6} \). So, if you have a velocity of 90 km/h:
    \[ v = 90 \times \frac{1}{3.6} \approx 25 \, \text{m/s} \]
This conversion is critical in problems where accurate linear momentum calculations are necessary. Always check the units first before proceeding with calculations.
Momentum Calculation
With mass and velocity understood and units correctly converted, you're ready to calculate momentum. Linear momentum is calculated using the formula:
\[ p = mv \]Where \(p\) represents momentum, \(m\) is mass, and \(v\) is velocity.
  • For a bowling ball with mass \(7.1 \, \text{kg}\) and velocity \(12 \, \text{m/s}\):
    \[ p = 7.1 \, \text{kg} \times 12 \, \text{m/s} = 85.2 \, \text{kg} \cdot \text{m/s} \]
  • For an automobile weighing \(1200 \, \text{kg}\) moving at \(25 \, \text{m/s}\) (after converting from 90 km/h):
    \[ p = 1200 \, \text{kg} \times 25 \, \text{m/s} = 30000 \, \text{kg} \cdot \text{m/s} \]
This straightforward calculation allows us to understand and compare the momentum of different objects, showcasing the relationship between mass, velocity, and the concept of inertia.

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Most popular questions from this chapter

A \(170-\mathrm{g}\) hockey puck sliding on ice perpendicularly impacts a flat piece of sideboard. Its incoming momentum is \(6.10 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\). It rebounds along its incoming path after having suffered a momentum change (magnitude) of \(8.80 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\). (a) If the impact with the board took \(35.0 \mathrm{~ms}\), determine the average force (including direction) exerted by the puck on the board. (b) Determine the final momentum of the puck. (c) Was this collision elastic or inelastic? Prove your answer mathematically.

A 1600 -kg (empty) truck rolls with a speed of \(2.5 \mathrm{~m} / \mathrm{s}\) under a loading bin, and a mass of \(3500 \mathrm{~kg}\) is deposited into the truck. What is the truck's speed immediately after loading?

An incoming 0.14 -kg baseball has a speed of \(45 \mathrm{~m} / \mathrm{s}\). The batter hits the ball, giving it a speed of \(60 \mathrm{~m} / \mathrm{s}\). If the contact time is \(0.040 \mathrm{~s},\) what is the average force of the bat on the ball?

Two ice skaters not paying attention collide in a completely inelastic collision. Prior to the collision, skater 1 , with a mass of \(60 \mathrm{~kg},\) has a velocity of \(5.0 \mathrm{~km} / \mathrm{h}\) eastward, and moves at a right angle to skater \(2,\) who has a mass of \(75 \mathrm{~kg}\) and a velocity of \(7.5 \mathrm{~km} / \mathrm{h}\) southward. What is the velocity of the skaters after collision?

You are traveling north and make a \(90^{\circ}\) right-hand turn east on a flat road while driving a car that has a total weight of 3600 lb. Before the turn, the car was traveling at \(40 \mathrm{mi} / \mathrm{h},\) and after the turn is completed you have slowed to \(30 \mathrm{mi} / \mathrm{h}\). If the turn took \(4.25 \mathrm{~s}\) to complete, determine the following: (a) the car's change in kinetic energy, (b) the car's change in momentum (including direction), and (c) the average net force exerted on the car during the turn (including direction).

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