/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 An incoming 0.14 -kg baseball ha... [FREE SOLUTION] | 91Ó°ÊÓ

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An incoming 0.14 -kg baseball has a speed of \(45 \mathrm{~m} / \mathrm{s}\). The batter hits the ball, giving it a speed of \(60 \mathrm{~m} / \mathrm{s}\). If the contact time is \(0.040 \mathrm{~s},\) what is the average force of the bat on the ball?

Short Answer

Expert verified
The average force is 52.5 N.

Step by step solution

01

Identify known values

Firstly, gather all the values given in the problem. The mass of the baseball is \( m = 0.14 \, \text{kg} \), the initial speed \( v_i = 45 \, \text{m/s} \), the final speed \( v_f = 60 \, \text{m/s} \), and the contact time \( \Delta t = 0.040 \, \text{s} \).
02

Calculate the change in velocity

Use the initial and final velocities to find the change in velocity (\( \Delta v \)) of the baseball. \( \Delta v = v_f - v_i = 60 \, \text{m/s} - 45 \, \text{m/s} = 15 \, \text{m/s} \).
03

Determine the change in momentum

The change in momentum (\( \Delta p \)) is given by \( \Delta p = m \cdot \Delta v \). Substitute the known values into the equation: \( \Delta p = 0.14 \, \text{kg} \times 15 \, \text{m/s} = 2.1 \, \text{kg} \cdot \text{m/s} \).
04

Calculate the average force

The average force (\( F \)) on the baseball is the change in momentum divided by the contact time: \( F = \frac{\Delta p}{\Delta t} \). Substituting the known values: \( F = \frac{2.1 \, \text{kg} \cdot \text{m/s}}{0.040 \, \text{s}} = 52.5 \, \text{N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
Momentum is a fundamental concept in physics, closely linked to both mass and velocity. It encapsulates the idea of how much "motion" an object possesses. Mathematically, momentum (\( p \)) is expressed as the product of an object's mass (\( m \)) and its velocity (\( v \)).
  • Formula: \( p = m \, \cdot \, v \)
  • Units: kgâ‹…m/s
A moving baseball is a great example to understand momentum in action. A heavier object moving at the same speed as a lighter one will have more momentum. Similarly, a faster object will have more momentum than a slower one, given equal mass. In our baseball scenario, momentum changes as the speed changes from 45 m/s to 60 m/s due to an external force (the bat).
The concept helps us quantify motion precisely, offering a base to calculate how forces will affect an object's state of movement.
Change in Velocity
Change in velocity (\( \Delta v \)) is essential for understanding how speed or direction alterations affect an object. In equations and analysis, it helps in measuring the impact of a force over time.
  • Formula: \( \Delta v = v_f - v_i \)
Here, \( v_f \) is the final velocity, and \( v_i \) is the initial velocity. For our baseball, it moves from an initial speed of 45 m/s to a final speed of 60 m/s. Thus, \( \Delta v = 60 \, \text{m/s} - 45 \, \text{m/s} = 15 \, \text{m/s} \).
The change in velocity directly influences momentum changes, and as shown, becomes crucial while calculating the average force applied during the contact time with the bat. It signifies the overall impact made on the baseball’s speed by the external force.
Impulse
Impulse is closely tied with the concepts of force and time. It describes how much momentum changes as a result of a force acting over a certain period. Impulse is crucial for understanding collisions and impact scenarios.
  • Formula: Impulse (\( J \)) = \( F \times \Delta t \)
  • Also expressed as the Change in Momentum: \( J = \Delta p \)
In the baseball example, we calculated the change in momentum to be \( 2.1 \text{ kg}\cdot\text{m/s} \). This is equivalent to the impulse involved because the change resulted from the bat's action during the 0.040 s of contact.
Hence, average force is derived using impulse over the time interval, emphasizing that both magnitude and duration of force impact an object's motion significantly. Understanding impulse helps grasp how any object's motion can be altered or controlled through force application over time.

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Most popular questions from this chapter

Two runners of mass \(70 \mathrm{~kg}\) and \(60 \mathrm{~kg}\), respectively, have a total linear momentum of \(350 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\). The heavier runner is running at \(2.0 \mathrm{~m} / \mathrm{s}\). Determine the possible velocities of the lighter runner.

At a shooting competition, a contestant fires and a 12.0-g bullet leaves the rifle with a muzzle speed of \(130 \mathrm{~m} / \mathrm{s}\). The bullet hits the thick target backing and stops after traveling \(4.00 \mathrm{~cm}\). Assuming a uniform acceleration, (a) what is the impulse on the target? (b) What is the average force on the target?

For a movie scene, a 75-kg stuntman drops from a tree onto a \(50-\mathrm{kg}\) sled that is moving on a frozen lake with a velocity of \(10 \mathrm{~m} / \mathrm{s}\) toward the shore. (a) What is the speed of the sled after the stuntman is on board? (b) If the sled hits the bank and stops, but the stuntman keeps on going, with what speed does he leave the sled? (Neglect friction.)

You are traveling north and make a \(90^{\circ}\) right-hand turn east on a flat road while driving a car that has a total weight of 3600 lb. Before the turn, the car was traveling at \(40 \mathrm{mi} / \mathrm{h},\) and after the turn is completed you have slowed to \(30 \mathrm{mi} / \mathrm{h}\). If the turn took \(4.25 \mathrm{~s}\) to complete, determine the following: (a) the car's change in kinetic energy, (b) the car's change in momentum (including direction), and (c) the average net force exerted on the car during the turn (including direction).

A 1600 -kg (empty) truck rolls with a speed of \(2.5 \mathrm{~m} / \mathrm{s}\) under a loading bin, and a mass of \(3500 \mathrm{~kg}\) is deposited into the truck. What is the truck's speed immediately after loading?

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